Metamath Proof Explorer


Theorem trclfvss

Description: The transitive closure (as a relation) of a subclass is a subclass of the transitive closure. (Contributed by RP, 3-May-2020)

Ref Expression
Assertion trclfvss ⊢ R ∈ V ∧ S ∈ W ∧ R ⊆ S → t+ ⁡ R ⊆ t+ ⁡ S

Proof

Step Hyp Ref Expression
1 trclsslem ⊢ R ⊆ S → ⋂ r | R ⊆ r ∧ r ∘ r ⊆ r ⊆ ⋂ r | S ⊆ r ∧ r ∘ r ⊆ r
2 1 3ad2ant3 ⊢ R ∈ V ∧ S ∈ W ∧ R ⊆ S → ⋂ r | R ⊆ r ∧ r ∘ r ⊆ r ⊆ ⋂ r | S ⊆ r ∧ r ∘ r ⊆ r
3 trclfv ⊢ R ∈ V → t+ ⁡ R = ⋂ r | R ⊆ r ∧ r ∘ r ⊆ r
4 3 3ad2ant1 ⊢ R ∈ V ∧ S ∈ W ∧ R ⊆ S → t+ ⁡ R = ⋂ r | R ⊆ r ∧ r ∘ r ⊆ r
5 trclfv ⊢ S ∈ W → t+ ⁡ S = ⋂ r | S ⊆ r ∧ r ∘ r ⊆ r
6 5 3ad2ant2 ⊢ R ∈ V ∧ S ∈ W ∧ R ⊆ S → t+ ⁡ S = ⋂ r | S ⊆ r ∧ r ∘ r ⊆ r
7 2 4 6 3sstr4d ⊢ R ∈ V ∧ S ∈ W ∧ R ⊆ S → t+ ⁡ R ⊆ t+ ⁡ S