Metamath Proof Explorer


Theorem vrgpinv

Description: The inverse of a generating element is represented by <. A , 1 >. instead of <. A , 0 >. . (Contributed by Mario Carneiro, 2-Oct-2015)

Ref Expression
Hypotheses vrgpfval.r ⊢ ∼ ˙ = ~ FG ⁡ I
vrgpfval.u ⊢ U = var FGrp ⁡ I
vrgpf.m ⊢ G = freeGrp ⁡ I
vrgpinv.n ⊢ N = inv g ⁡ G
Assertion vrgpinv ⊢ I ∈ V ∧ A ∈ I → N ⁡ U ⁡ A = ⟨“ A 1 𝑜 ”⟩ ∼ ˙

Proof

Step Hyp Ref Expression
1 vrgpfval.r ⊢ ∼ ˙ = ~ FG ⁡ I
2 vrgpfval.u ⊢ U = var FGrp ⁡ I
3 vrgpf.m ⊢ G = freeGrp ⁡ I
4 vrgpinv.n ⊢ N = inv g ⁡ G
5 1 2 vrgpval ⊢ I ∈ V ∧ A ∈ I → U ⁡ A = ⟨“ A ∅ ”⟩ ∼ ˙
6 5 fveq2d ⊢ I ∈ V ∧ A ∈ I → N ⁡ U ⁡ A = N ⁡ ⟨“ A ∅ ”⟩ ∼ ˙
7 simpr ⊢ I ∈ V ∧ A ∈ I → A ∈ I
8 0ex ⊢ ∅ ∈ V
9 8 prid1 ⊢ ∅ ∈ ∅ 1 𝑜
10 df2o3 ⊢ 2 𝑜 = ∅ 1 𝑜
11 9 10 eleqtrri ⊢ ∅ ∈ 2 𝑜
12 opelxpi ⊢ A ∈ I ∧ ∅ ∈ 2 𝑜 → A ∅ ∈ I × 2 𝑜
13 7 11 12 sylancl ⊢ I ∈ V ∧ A ∈ I → A ∅ ∈ I × 2 𝑜
14 13 s1cld ⊢ I ∈ V ∧ A ∈ I → ⟨“ A ∅ ”⟩ ∈ Word I × 2 𝑜
15 simpl ⊢ I ∈ V ∧ A ∈ I → I ∈ V
16 2on ⊢ 2 𝑜 ∈ On
17 xpexg ⊢ I ∈ V ∧ 2 𝑜 ∈ On → I × 2 𝑜 ∈ V
18 15 16 17 sylancl ⊢ I ∈ V ∧ A ∈ I → I × 2 𝑜 ∈ V
19 wrdexg ⊢ I × 2 𝑜 ∈ V → Word I × 2 𝑜 ∈ V
20 fvi ⊢ Word I × 2 𝑜 ∈ V → I ⁡ Word I × 2 𝑜 = Word I × 2 𝑜
21 18 19 20 3syl ⊢ I ∈ V ∧ A ∈ I → I ⁡ Word I × 2 𝑜 = Word I × 2 𝑜
22 14 21 eleqtrrd ⊢ I ∈ V ∧ A ∈ I → ⟨“ A ∅ ”⟩ ∈ I ⁡ Word I × 2 𝑜
23 eqid ⊢ I ⁡ Word I × 2 𝑜 = I ⁡ Word I × 2 𝑜
24 eqid ⊢ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y = x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y
25 23 3 1 4 24 frgpinv ⊢ ⟨“ A ∅ ”⟩ ∈ I ⁡ Word I × 2 𝑜 → N ⁡ ⟨“ A ∅ ”⟩ ∼ ˙ = x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ reverse ⁡ ⟨“ A ∅ ”⟩ ∼ ˙
26 22 25 syl ⊢ I ∈ V ∧ A ∈ I → N ⁡ ⟨“ A ∅ ”⟩ ∼ ˙ = x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ reverse ⁡ ⟨“ A ∅ ”⟩ ∼ ˙
27 revs1 ⊢ reverse ⁡ ⟨“ A ∅ ”⟩ = ⟨“ A ∅ ”⟩
28 27 a1i ⊢ I ∈ V ∧ A ∈ I → reverse ⁡ ⟨“ A ∅ ”⟩ = ⟨“ A ∅ ”⟩
29 28 coeq2d ⊢ I ∈ V ∧ A ∈ I → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ reverse ⁡ ⟨“ A ∅ ”⟩ = x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ ⟨“ A ∅ ”⟩
30 24 efgmf ⊢ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y : I × 2 𝑜 ⟶ I × 2 𝑜
31 s1co ⊢ A ∅ ∈ I × 2 𝑜 ∧ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y : I × 2 𝑜 ⟶ I × 2 𝑜 → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ ⟨“ A ∅ ”⟩ = ⟨“ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ⁡ A ∅ ”⟩
32 13 30 31 sylancl ⊢ I ∈ V ∧ A ∈ I → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ ⟨“ A ∅ ”⟩ = ⟨“ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ⁡ A ∅ ”⟩
33 24 efgmval ⊢ A ∈ I ∧ ∅ ∈ 2 𝑜 → A x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∅ = A 1 𝑜 ∖ ∅
34 7 11 33 sylancl ⊢ I ∈ V ∧ A ∈ I → A x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∅ = A 1 𝑜 ∖ ∅
35 df-ov ⊢ A x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∅ = x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ⁡ A ∅
36 dif0 ⊢ 1 𝑜 ∖ ∅ = 1 𝑜
37 36 opeq2i ⊢ A 1 𝑜 ∖ ∅ = A 1 𝑜
38 34 35 37 3eqtr3g ⊢ I ∈ V ∧ A ∈ I → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ⁡ A ∅ = A 1 𝑜
39 38 s1eqd ⊢ I ∈ V ∧ A ∈ I → ⟨“ x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ⁡ A ∅ ”⟩ = ⟨“ A 1 𝑜 ”⟩
40 29 32 39 3eqtrd ⊢ I ∈ V ∧ A ∈ I → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ reverse ⁡ ⟨“ A ∅ ”⟩ = ⟨“ A 1 𝑜 ”⟩
41 40 eceq1d ⊢ I ∈ V ∧ A ∈ I → x ∈ I , y ∈ 2 𝑜 ⟼ x 1 𝑜 ∖ y ∘ reverse ⁡ ⟨“ A ∅ ”⟩ ∼ ˙ = ⟨“ A 1 𝑜 ”⟩ ∼ ˙
42 6 26 41 3eqtrd ⊢ I ∈ V ∧ A ∈ I → N ⁡ U ⁡ A = ⟨“ A 1 𝑜 ”⟩ ∼ ˙