Metamath Proof Explorer


Theorem acycgr2v

Description: A simple graph with two vertices is an acyclic graph. (Contributed by BTernaryTau, 12-Oct-2023)

Ref Expression
Hypothesis acycgrv.1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
Assertion acycgr2v ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → 𝐺 ∈ AcyclicGraph )

Proof

Step Hyp Ref Expression
1 acycgrv.1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
2 1 usgrcyclgt2v ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → 2 < ( ♯ ‘ 𝑉 ) )
3 2re ⊢ 2 ∈ ℝ
4 3 rexri ⊢ 2 ∈ ℝ*
5 1 fvexi ⊢ 𝑉 ∈ V
6 hashxrcl ⊢ ( 𝑉 ∈ V → ( ♯ ‘ 𝑉 ) ∈ ℝ* )
7 5 6 ax-mp ⊢ ( ♯ ‘ 𝑉 ) ∈ ℝ*
8 xrltne ⊢ ( ( 2 ∈ ℝ* ∧ ( ♯ ‘ 𝑉 ) ∈ ℝ* ∧ 2 < ( ♯ ‘ 𝑉 ) ) → ( ♯ ‘ 𝑉 ) ≠ 2 )
9 4 7 8 mp3an12 ⊢ ( 2 < ( ♯ ‘ 𝑉 ) → ( ♯ ‘ 𝑉 ) ≠ 2 )
10 9 neneqd ⊢ ( 2 < ( ♯ ‘ 𝑉 ) → ¬ ( ♯ ‘ 𝑉 ) = 2 )
11 2 10 syl ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → ¬ ( ♯ ‘ 𝑉 ) = 2 )
12 11 3expib ⊢ ( 𝐺 ∈ USGraph → ( ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → ¬ ( ♯ ‘ 𝑉 ) = 2 ) )
13 12 con2d ⊢ ( 𝐺 ∈ USGraph → ( ( ♯ ‘ 𝑉 ) = 2 → ¬ ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
14 13 imp ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → ¬ ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) )
15 14 nexdv ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → ¬ ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) )
16 15 nexdv ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) )
17 isacycgr ⊢ ( 𝐺 ∈ USGraph → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
18 17 adantr ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
19 16 18 mpbird ⊢ ( ( 𝐺 ∈ USGraph ∧ ( ♯ ‘ 𝑉 ) = 2 ) → 𝐺 ∈ AcyclicGraph )