Metamath Proof Explorer


Theorem bj-ccinftydisj

Description: The circle at infinity is disjoint from the set of complex numbers. (Contributed by BJ, 22-Jun-2019)

Ref Expression
Assertion bj-ccinftydisj ( ℂ ∩ ℂ∞ ) = ∅

Proof

Step Hyp Ref Expression
1 bj-inftyexpidisj ⊢ ¬ ( +∞ei ‘ 𝑦 ) ∈ ℂ
2 1 nex ⊢ ¬ ∃ 𝑦 ( +∞ei ‘ 𝑦 ) ∈ ℂ
3 elin ⊢ ( 𝑥 ∈ ( ℂ ∩ ℂ∞ ) ↔ ( 𝑥 ∈ ℂ ∧ 𝑥 ∈ ℂ∞ ) )
4 df-bj-inftyexpi ⊢ +∞ei = ( 𝑧 ∈ ( - π (,] π ) ↦ ⟨ 𝑧 , ℂ ⟩ )
5 4 funmpt2 ⊢ Fun +∞ei
6 elrnrexdm ⊢ ( Fun +∞ei → ( 𝑥 ∈ ran +∞ei → ∃ 𝑦 ∈ dom +∞ei 𝑥 = ( +∞ei ‘ 𝑦 ) ) )
7 5 6 ax-mp ⊢ ( 𝑥 ∈ ran +∞ei → ∃ 𝑦 ∈ dom +∞ei 𝑥 = ( +∞ei ‘ 𝑦 ) )
8 rexex ⊢ ( ∃ 𝑦 ∈ dom +∞ei 𝑥 = ( +∞ei ‘ 𝑦 ) → ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) )
9 7 8 syl ⊢ ( 𝑥 ∈ ran +∞ei → ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) )
10 df-bj-ccinfty ⊢ ℂ∞ = ran +∞ei
11 9 10 eleq2s ⊢ ( 𝑥 ∈ ℂ∞ → ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) )
12 11 anim2i ⊢ ( ( 𝑥 ∈ ℂ ∧ 𝑥 ∈ ℂ∞ ) → ( 𝑥 ∈ ℂ ∧ ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ) )
13 3 12 sylbi ⊢ ( 𝑥 ∈ ( ℂ ∩ ℂ∞ ) → ( 𝑥 ∈ ℂ ∧ ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ) )
14 ancom ⊢ ( ( 𝑥 ∈ ℂ ∧ ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ) ↔ ( ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ∧ 𝑥 ∈ ℂ ) )
15 exancom ⊢ ( ∃ 𝑦 ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) ↔ ∃ 𝑦 ( 𝑥 = ( +∞ei ‘ 𝑦 ) ∧ 𝑥 ∈ ℂ ) )
16 19.41v ⊢ ( ∃ 𝑦 ( 𝑥 = ( +∞ei ‘ 𝑦 ) ∧ 𝑥 ∈ ℂ ) ↔ ( ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ∧ 𝑥 ∈ ℂ ) )
17 15 16 bitri ⊢ ( ∃ 𝑦 ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) ↔ ( ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ∧ 𝑥 ∈ ℂ ) )
18 14 17 sylbb2 ⊢ ( ( 𝑥 ∈ ℂ ∧ ∃ 𝑦 𝑥 = ( +∞ei ‘ 𝑦 ) ) → ∃ 𝑦 ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) )
19 13 18 syl ⊢ ( 𝑥 ∈ ( ℂ ∩ ℂ∞ ) → ∃ 𝑦 ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) )
20 eleq1 ⊢ ( 𝑥 = ( +∞ei ‘ 𝑦 ) → ( 𝑥 ∈ ℂ ↔ ( +∞ei ‘ 𝑦 ) ∈ ℂ ) )
21 20 biimpac ⊢ ( ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) → ( +∞ei ‘ 𝑦 ) ∈ ℂ )
22 21 eximi ⊢ ( ∃ 𝑦 ( 𝑥 ∈ ℂ ∧ 𝑥 = ( +∞ei ‘ 𝑦 ) ) → ∃ 𝑦 ( +∞ei ‘ 𝑦 ) ∈ ℂ )
23 19 22 syl ⊢ ( 𝑥 ∈ ( ℂ ∩ ℂ∞ ) → ∃ 𝑦 ( +∞ei ‘ 𝑦 ) ∈ ℂ )
24 2 23 mto ⊢ ¬ 𝑥 ∈ ( ℂ ∩ ℂ∞ )
25 24 nel0 ⊢ ( ℂ ∩ ℂ∞ ) = ∅