Metamath Proof Explorer


Theorem bj-rest10

Description: An elementwise intersection on a nonempty family by the empty set is the singleton on the empty set. TODO: this generalizes rest0 and could replace it. (Contributed by BJ, 27-Apr-2021)

Ref Expression
Assertion bj-rest10 ( 𝑋 ∈ 𝑉 → ( 𝑋 ≠ ∅ → ( 𝑋 ↾t ∅ ) = { ∅ } ) )

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 elrest ⊢ ( ( 𝑋 ∈ 𝑉 ∧ ∅ ∈ V ) → ( 𝑥 ∈ ( 𝑋 ↾t ∅ ) ↔ ∃ 𝑦 ∈ 𝑋 𝑥 = ( 𝑦 ∩ ∅ ) ) )
3 1 2 mpan2 ⊢ ( 𝑋 ∈ 𝑉 → ( 𝑥 ∈ ( 𝑋 ↾t ∅ ) ↔ ∃ 𝑦 ∈ 𝑋 𝑥 = ( 𝑦 ∩ ∅ ) ) )
4 in0 ⊢ ( 𝑦 ∩ ∅ ) = ∅
5 4 eqeq2i ⊢ ( 𝑥 = ( 𝑦 ∩ ∅ ) ↔ 𝑥 = ∅ )
6 5 rexbii ⊢ ( ∃ 𝑦 ∈ 𝑋 𝑥 = ( 𝑦 ∩ ∅ ) ↔ ∃ 𝑦 ∈ 𝑋 𝑥 = ∅ )
7 df-rex ⊢ ( ∃ 𝑦 ∈ 𝑋 𝑥 = ∅ ↔ ∃ 𝑦 ( 𝑦 ∈ 𝑋 ∧ 𝑥 = ∅ ) )
8 19.41v ⊢ ( ∃ 𝑦 ( 𝑦 ∈ 𝑋 ∧ 𝑥 = ∅ ) ↔ ( ∃ 𝑦 𝑦 ∈ 𝑋 ∧ 𝑥 = ∅ ) )
9 n0 ⊢ ( 𝑋 ≠ ∅ ↔ ∃ 𝑦 𝑦 ∈ 𝑋 )
10 9 bicomi ⊢ ( ∃ 𝑦 𝑦 ∈ 𝑋 ↔ 𝑋 ≠ ∅ )
11 10 anbi1i ⊢ ( ( ∃ 𝑦 𝑦 ∈ 𝑋 ∧ 𝑥 = ∅ ) ↔ ( 𝑋 ≠ ∅ ∧ 𝑥 = ∅ ) )
12 8 11 bitri ⊢ ( ∃ 𝑦 ( 𝑦 ∈ 𝑋 ∧ 𝑥 = ∅ ) ↔ ( 𝑋 ≠ ∅ ∧ 𝑥 = ∅ ) )
13 7 12 bitri ⊢ ( ∃ 𝑦 ∈ 𝑋 𝑥 = ∅ ↔ ( 𝑋 ≠ ∅ ∧ 𝑥 = ∅ ) )
14 6 13 bitri ⊢ ( ∃ 𝑦 ∈ 𝑋 𝑥 = ( 𝑦 ∩ ∅ ) ↔ ( 𝑋 ≠ ∅ ∧ 𝑥 = ∅ ) )
15 14 baib ⊢ ( 𝑋 ≠ ∅ → ( ∃ 𝑦 ∈ 𝑋 𝑥 = ( 𝑦 ∩ ∅ ) ↔ 𝑥 = ∅ ) )
16 3 15 sylan9bb ⊢ ( ( 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ ∅ ) → ( 𝑥 ∈ ( 𝑋 ↾t ∅ ) ↔ 𝑥 = ∅ ) )
17 velsn ⊢ ( 𝑥 ∈ { ∅ } ↔ 𝑥 = ∅ )
18 16 17 bitr4di ⊢ ( ( 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ ∅ ) → ( 𝑥 ∈ ( 𝑋 ↾t ∅ ) ↔ 𝑥 ∈ { ∅ } ) )
19 18 eqrdv ⊢ ( ( 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ ∅ ) → ( 𝑋 ↾t ∅ ) = { ∅ } )
20 19 ex ⊢ ( 𝑋 ∈ 𝑉 → ( 𝑋 ≠ ∅ → ( 𝑋 ↾t ∅ ) = { ∅ } ) )