Metamath Proof Explorer


Theorem cocnv

Description: Composition with a function and then with the converse. (Contributed by Jeff Madsen, 2-Sep-2009)

Ref Expression
Assertion cocnv ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( ( 𝐹𝐺 ) ∘ 𝐺 ) = ( 𝐹 ↾ ran 𝐺 ) )

Proof

Step Hyp Ref Expression
1 coass ( ( 𝐹𝐺 ) ∘ 𝐺 ) = ( 𝐹 ∘ ( 𝐺 𝐺 ) )
2 funcocnv2 ( Fun 𝐺 → ( 𝐺 𝐺 ) = ( I ↾ ran 𝐺 ) )
3 2 adantl ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( 𝐺 𝐺 ) = ( I ↾ ran 𝐺 ) )
4 3 coeq2d ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( 𝐹 ∘ ( 𝐺 𝐺 ) ) = ( 𝐹 ∘ ( I ↾ ran 𝐺 ) ) )
5 resco ( ( 𝐹 ∘ I ) ↾ ran 𝐺 ) = ( 𝐹 ∘ ( I ↾ ran 𝐺 ) )
6 funrel ( Fun 𝐹 → Rel 𝐹 )
7 coi1 ( Rel 𝐹 → ( 𝐹 ∘ I ) = 𝐹 )
8 6 7 syl ( Fun 𝐹 → ( 𝐹 ∘ I ) = 𝐹 )
9 8 reseq1d ( Fun 𝐹 → ( ( 𝐹 ∘ I ) ↾ ran 𝐺 ) = ( 𝐹 ↾ ran 𝐺 ) )
10 9 adantr ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( ( 𝐹 ∘ I ) ↾ ran 𝐺 ) = ( 𝐹 ↾ ran 𝐺 ) )
11 5 10 eqtr3id ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( 𝐹 ∘ ( I ↾ ran 𝐺 ) ) = ( 𝐹 ↾ ran 𝐺 ) )
12 4 11 eqtrd ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( 𝐹 ∘ ( 𝐺 𝐺 ) ) = ( 𝐹 ↾ ran 𝐺 ) )
13 1 12 syl5eq ( ( Fun 𝐹 ∧ Fun 𝐺 ) → ( ( 𝐹𝐺 ) ∘ 𝐺 ) = ( 𝐹 ↾ ran 𝐺 ) )