Metamath Proof Explorer


Theorem inaex

Description: Assuming the Tarski-Grothendieck axiom, every ordinal is contained in an inaccessible ordinal. (Contributed by Rohan Ridenour, 13-Aug-2023)

Ref Expression
Assertion inaex ( 𝐴 ∈ On → ∃ 𝑥 ∈ Inacc 𝐴 ∈ 𝑥 )

Proof

Step Hyp Ref Expression
1 inawina ⊢ ( 𝑥 ∈ Inacc → 𝑥 ∈ Inaccw )
2 winaon ⊢ ( 𝑥 ∈ Inaccw → 𝑥 ∈ On )
3 1 2 syl ⊢ ( 𝑥 ∈ Inacc → 𝑥 ∈ On )
4 3 ssriv ⊢ Inacc ⊆ On
5 onmindif ⊢ ( ( Inacc ⊆ On ∧ 𝐴 ∈ On ) → 𝐴 ∈ ∩ ( Inacc ∖ suc 𝐴 ) )
6 4 5 mpan ⊢ ( 𝐴 ∈ On → 𝐴 ∈ ∩ ( Inacc ∖ suc 𝐴 ) )
7 6 adantr ⊢ ( ( 𝐴 ∈ On ∧ 𝑥 = ∩ ( Inacc ∖ suc 𝐴 ) ) → 𝐴 ∈ ∩ ( Inacc ∖ suc 𝐴 ) )
8 simpr ⊢ ( ( 𝐴 ∈ On ∧ 𝑥 = ∩ ( Inacc ∖ suc 𝐴 ) ) → 𝑥 = ∩ ( Inacc ∖ suc 𝐴 ) )
9 7 8 eleqtrrd ⊢ ( ( 𝐴 ∈ On ∧ 𝑥 = ∩ ( Inacc ∖ suc 𝐴 ) ) → 𝐴 ∈ 𝑥 )
10 difss ⊢ ( Inacc ∖ suc 𝐴 ) ⊆ Inacc
11 10 4 sstri ⊢ ( Inacc ∖ suc 𝐴 ) ⊆ On
12 inaprc ⊢ Inacc ∉ V
13 12 neli ⊢ ¬ Inacc ∈ V
14 ssdif0 ⊢ ( Inacc ⊆ suc 𝐴 ↔ ( Inacc ∖ suc 𝐴 ) = ∅ )
15 sucexg ⊢ ( 𝐴 ∈ On → suc 𝐴 ∈ V )
16 ssexg ⊢ ( ( Inacc ⊆ suc 𝐴 ∧ suc 𝐴 ∈ V ) → Inacc ∈ V )
17 16 expcom ⊢ ( suc 𝐴 ∈ V → ( Inacc ⊆ suc 𝐴 → Inacc ∈ V ) )
18 15 17 syl ⊢ ( 𝐴 ∈ On → ( Inacc ⊆ suc 𝐴 → Inacc ∈ V ) )
19 14 18 biimtrrid ⊢ ( 𝐴 ∈ On → ( ( Inacc ∖ suc 𝐴 ) = ∅ → Inacc ∈ V ) )
20 13 19 mtoi ⊢ ( 𝐴 ∈ On → ¬ ( Inacc ∖ suc 𝐴 ) = ∅ )
21 20 neqned ⊢ ( 𝐴 ∈ On → ( Inacc ∖ suc 𝐴 ) ≠ ∅ )
22 onint ⊢ ( ( ( Inacc ∖ suc 𝐴 ) ⊆ On ∧ ( Inacc ∖ suc 𝐴 ) ≠ ∅ ) → ∩ ( Inacc ∖ suc 𝐴 ) ∈ ( Inacc ∖ suc 𝐴 ) )
23 11 21 22 sylancr ⊢ ( 𝐴 ∈ On → ∩ ( Inacc ∖ suc 𝐴 ) ∈ ( Inacc ∖ suc 𝐴 ) )
24 23 eldifad ⊢ ( 𝐴 ∈ On → ∩ ( Inacc ∖ suc 𝐴 ) ∈ Inacc )
25 9 24 rspcime ⊢ ( 𝐴 ∈ On → ∃ 𝑥 ∈ Inacc 𝐴 ∈ 𝑥 )