Theorem invdisjrabw

Description: Version of invdisjrab with a disjoint variable condition, which does not require ax-13 . (Contributed by Gino Giotto, 26-Jan-2024)

	Ref	Expression
Assertion	invdisjrabw	⊢ Disj 𝑦 ∈ 𝐴 { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 }

Proof

Step	Hyp	Ref	Expression
1		nfcv	⊢ Ⅎ 𝑥 𝑧
2		nfcv	⊢ Ⅎ 𝑥 𝐵
3		nfcsb1v	⊢ Ⅎ 𝑥 ⦋ 𝑧 / 𝑥 ⦌ 𝐶
4	3	nfeq1	⊢ Ⅎ 𝑥 ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦
5		csbeq1a	⊢ ( 𝑥 = 𝑧 → 𝐶 = ⦋ 𝑧 / 𝑥 ⦌ 𝐶 )
6	5	eqeq1d	⊢ ( 𝑥 = 𝑧 → ( 𝐶 = 𝑦 ↔ ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 ) )
7	1 2 4 6	elrabf	⊢ ( 𝑧 ∈ { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 } ↔ ( 𝑧 ∈ 𝐵 ∧ ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 ) )
8		simprr	⊢ ( ( 𝑦 ∈ 𝐴 ∧ ( 𝑧 ∈ 𝐵 ∧ ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 ) ) → ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 )
9	7 8	sylan2b	⊢ ( ( 𝑦 ∈ 𝐴 ∧ 𝑧 ∈ { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 } ) → ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 )
10	9	rgen2	⊢ ∀ 𝑦 ∈ 𝐴 ∀ 𝑧 ∈ { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 } ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦
11		invdisj	⊢ ( ∀ 𝑦 ∈ 𝐴 ∀ 𝑧 ∈ { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 } ⦋ 𝑧 / 𝑥 ⦌ 𝐶 = 𝑦 → Disj 𝑦 ∈ 𝐴 { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 } )
12	10 11	ax-mp	⊢ Disj 𝑦 ∈ 𝐴 { 𝑥 ∈ 𝐵 ∣ 𝐶 = 𝑦 }