Metamath Proof Explorer


Theorem limexissupab

Description: An ordinal which is a limit ordinal is equal to the supremum of the class of all its elements. Lemma 2.13 of Schloeder p. 5. (Contributed by RP, 27-Jan-2025)

Ref Expression
Assertion limexissupab ( ( Lim 𝐴 ∧ 𝐴 ∈ 𝑉 ) → 𝐴 = sup ( { 𝑥 ∣ 𝑥 ∈ 𝐴 } , On , E ) )

Proof

Step Hyp Ref Expression
1 limuni ⊢ ( Lim 𝐴 → 𝐴 = ∪ 𝐴 )
2 1 adantr ⊢ ( ( Lim 𝐴 ∧ 𝐴 ∈ 𝑉 ) → 𝐴 = ∪ 𝐴 )
3 limord ⊢ ( Lim 𝐴 → Ord 𝐴 )
4 ordsson ⊢ ( Ord 𝐴 → 𝐴 ⊆ On )
5 3 4 syl ⊢ ( Lim 𝐴 → 𝐴 ⊆ On )
6 onsupuni ⊢ ( ( 𝐴 ⊆ On ∧ 𝐴 ∈ 𝑉 ) → sup ( 𝐴 , On , E ) = ∪ 𝐴 )
7 5 6 sylan ⊢ ( ( Lim 𝐴 ∧ 𝐴 ∈ 𝑉 ) → sup ( 𝐴 , On , E ) = ∪ 𝐴 )
8 abid1 ⊢ 𝐴 = { 𝑥 ∣ 𝑥 ∈ 𝐴 }
9 supeq1 ⊢ ( 𝐴 = { 𝑥 ∣ 𝑥 ∈ 𝐴 } → sup ( 𝐴 , On , E ) = sup ( { 𝑥 ∣ 𝑥 ∈ 𝐴 } , On , E ) )
10 8 9 mp1i ⊢ ( ( Lim 𝐴 ∧ 𝐴 ∈ 𝑉 ) → sup ( 𝐴 , On , E ) = sup ( { 𝑥 ∣ 𝑥 ∈ 𝐴 } , On , E ) )
11 2 7 10 3eqtr2d ⊢ ( ( Lim 𝐴 ∧ 𝐴 ∈ 𝑉 ) → 𝐴 = sup ( { 𝑥 ∣ 𝑥 ∈ 𝐴 } , On , E ) )