Metamath Proof Explorer


Theorem nelsubginvcld

Description: The inverse of a non-subgroup-member is a non-subgroup-member. (Contributed by Steven Nguyen, 15-Apr-2023)

Ref Expression
Hypotheses nelsubginvcld.g ⊢ ( 𝜑 → 𝐺 ∈ Grp )
nelsubginvcld.s ⊢ ( 𝜑 → 𝑆 ∈ ( SubGrp ‘ 𝐺 ) )
nelsubginvcld.x ⊢ ( 𝜑 → 𝑋 ∈ ( 𝐵 ∖ 𝑆 ) )
nelsubginvcld.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
nelsubginvcld.p ⊢ 𝑁 = ( invg ‘ 𝐺 )
Assertion nelsubginvcld ( 𝜑 → ( 𝑁 ‘ 𝑋 ) ∈ ( 𝐵 ∖ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 nelsubginvcld.g ⊢ ( 𝜑 → 𝐺 ∈ Grp )
2 nelsubginvcld.s ⊢ ( 𝜑 → 𝑆 ∈ ( SubGrp ‘ 𝐺 ) )
3 nelsubginvcld.x ⊢ ( 𝜑 → 𝑋 ∈ ( 𝐵 ∖ 𝑆 ) )
4 nelsubginvcld.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
5 nelsubginvcld.p ⊢ 𝑁 = ( invg ‘ 𝐺 )
6 3 eldifad ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
7 4 5 grpinvcl ⊢ ( ( 𝐺 ∈ Grp ∧ 𝑋 ∈ 𝐵 ) → ( 𝑁 ‘ 𝑋 ) ∈ 𝐵 )
8 1 6 7 syl2anc ⊢ ( 𝜑 → ( 𝑁 ‘ 𝑋 ) ∈ 𝐵 )
9 3 eldifbd ⊢ ( 𝜑 → ¬ 𝑋 ∈ 𝑆 )
10 4 5 grpinvinv ⊢ ( ( 𝐺 ∈ Grp ∧ 𝑋 ∈ 𝐵 ) → ( 𝑁 ‘ ( 𝑁 ‘ 𝑋 ) ) = 𝑋 )
11 1 6 10 syl2anc ⊢ ( 𝜑 → ( 𝑁 ‘ ( 𝑁 ‘ 𝑋 ) ) = 𝑋 )
12 11 adantr ⊢ ( ( 𝜑 ∧ ( 𝑁 ‘ 𝑋 ) ∈ 𝑆 ) → ( 𝑁 ‘ ( 𝑁 ‘ 𝑋 ) ) = 𝑋 )
13 5 subginvcl ⊢ ( ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) ∧ ( 𝑁 ‘ 𝑋 ) ∈ 𝑆 ) → ( 𝑁 ‘ ( 𝑁 ‘ 𝑋 ) ) ∈ 𝑆 )
14 2 13 sylan ⊢ ( ( 𝜑 ∧ ( 𝑁 ‘ 𝑋 ) ∈ 𝑆 ) → ( 𝑁 ‘ ( 𝑁 ‘ 𝑋 ) ) ∈ 𝑆 )
15 12 14 eqeltrrd ⊢ ( ( 𝜑 ∧ ( 𝑁 ‘ 𝑋 ) ∈ 𝑆 ) → 𝑋 ∈ 𝑆 )
16 9 15 mtand ⊢ ( 𝜑 → ¬ ( 𝑁 ‘ 𝑋 ) ∈ 𝑆 )
17 8 16 eldifd ⊢ ( 𝜑 → ( 𝑁 ‘ 𝑋 ) ∈ ( 𝐵 ∖ 𝑆 ) )