Metamath Proof Explorer


Theorem newval

Description: The value of the new options function. (Contributed by Scott Fenton, 9-Oct-2024)

Ref Expression
Assertion newval ( N ‘ 𝐴 ) = ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ ( 𝑥 = 𝐴 → ( M ‘ 𝑥 ) = ( M ‘ 𝐴 ) )
2 fveq2 ⊢ ( 𝑥 = 𝐴 → ( O ‘ 𝑥 ) = ( O ‘ 𝐴 ) )
3 1 2 difeq12d ⊢ ( 𝑥 = 𝐴 → ( ( M ‘ 𝑥 ) ∖ ( O ‘ 𝑥 ) ) = ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) )
4 df-new ⊢ N = ( 𝑥 ∈ On ↦ ( ( M ‘ 𝑥 ) ∖ ( O ‘ 𝑥 ) ) )
5 fvex ⊢ ( M ‘ 𝐴 ) ∈ V
6 5 difexi ⊢ ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) ∈ V
7 3 4 6 fvmpt ⊢ ( 𝐴 ∈ On → ( N ‘ 𝐴 ) = ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) )
8 4 fvmptndm ⊢ ( ¬ 𝐴 ∈ On → ( N ‘ 𝐴 ) = ∅ )
9 df-made ⊢ M = recs ( ( 𝑓 ∈ V ↦ ( |s “ ( 𝒫 ∪ ran 𝑓 × 𝒫 ∪ ran 𝑓 ) ) ) )
10 9 tfr1 ⊢ M Fn On
11 10 fndmi ⊢ dom M = On
12 11 eleq2i ⊢ ( 𝐴 ∈ dom M ↔ 𝐴 ∈ On )
13 ndmfv ⊢ ( ¬ 𝐴 ∈ dom M → ( M ‘ 𝐴 ) = ∅ )
14 12 13 sylnbir ⊢ ( ¬ 𝐴 ∈ On → ( M ‘ 𝐴 ) = ∅ )
15 14 difeq1d ⊢ ( ¬ 𝐴 ∈ On → ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) = ( ∅ ∖ ( O ‘ 𝐴 ) ) )
16 0dif ⊢ ( ∅ ∖ ( O ‘ 𝐴 ) ) = ∅
17 15 16 eqtrdi ⊢ ( ¬ 𝐴 ∈ On → ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) = ∅ )
18 8 17 eqtr4d ⊢ ( ¬ 𝐴 ∈ On → ( N ‘ 𝐴 ) = ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) ) )
19 7 18 pm2.61i ⊢ ( N ‘ 𝐴 ) = ( ( M ‘ 𝐴 ) ∖ ( O ‘ 𝐴 ) )