Metamath Proof Explorer


Theorem newval

Description: The value of the new options function. (Contributed by Scott Fenton, 9-Oct-2024)

Ref Expression
Assertion newval ⊢ N ⁡ A = M ⁡ A ∖ Old ⁡ A

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ x = A → M ⁡ x = M ⁡ A
2 fveq2 ⊢ x = A → Old ⁡ x = Old ⁡ A
3 1 2 difeq12d ⊢ x = A → M ⁡ x ∖ Old ⁡ x = M ⁡ A ∖ Old ⁡ A
4 df-new ⊢ N = x ∈ On ⟼ M ⁡ x ∖ Old ⁡ x
5 fvex ⊢ M ⁡ A ∈ V
6 5 difexi ⊢ M ⁡ A ∖ Old ⁡ A ∈ V
7 3 4 6 fvmpt ⊢ A ∈ On → N ⁡ A = M ⁡ A ∖ Old ⁡ A
8 4 fvmptndm ⊢ ¬ A ∈ On → N ⁡ A = ∅
9 df-made ⊢ M = recs ⁡ f ∈ V ⟼ | s 𝒫 ⋃ ran ⁡ f × 𝒫 ⋃ ran ⁡ f
10 9 tfr1 ⊢ M Fn On
11 10 fndmi ⊢ dom ⁡ M = On
12 11 eleq2i ⊢ A ∈ dom ⁡ M ↔ A ∈ On
13 ndmfv ⊢ ¬ A ∈ dom ⁡ M → M ⁡ A = ∅
14 12 13 sylnbir ⊢ ¬ A ∈ On → M ⁡ A = ∅
15 14 difeq1d ⊢ ¬ A ∈ On → M ⁡ A ∖ Old ⁡ A = ∅ ∖ Old ⁡ A
16 0dif ⊢ ∅ ∖ Old ⁡ A = ∅
17 15 16 eqtrdi ⊢ ¬ A ∈ On → M ⁡ A ∖ Old ⁡ A = ∅
18 8 17 eqtr4d ⊢ ¬ A ∈ On → N ⁡ A = M ⁡ A ∖ Old ⁡ A
19 7 18 pm2.61i ⊢ N ⁡ A = M ⁡ A ∖ Old ⁡ A