Metamath Proof Explorer


Theorem ntrkbimka

Description: If the interiors of disjoint sets are disjoint, then the interior of the empty set is the empty set. (Contributed by RP, 14-Jun-2021)

Ref Expression
Assertion ntrkbimka ( ∀ 𝑠 ∈ 𝒫 𝐵𝑡 ∈ 𝒫 𝐵 ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) → ( 𝐼 ‘ ∅ ) = ∅ )

Proof

Step Hyp Ref Expression
1 inidm ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼 ‘ ∅ ) ) = ( 𝐼 ‘ ∅ )
2 0elpw ∅ ∈ 𝒫 𝐵
3 ineq1 ( 𝑠 = ∅ → ( 𝑠𝑡 ) = ( ∅ ∩ 𝑡 ) )
4 3 eqeq1d ( 𝑠 = ∅ → ( ( 𝑠𝑡 ) = ∅ ↔ ( ∅ ∩ 𝑡 ) = ∅ ) )
5 fveq2 ( 𝑠 = ∅ → ( 𝐼𝑠 ) = ( 𝐼 ‘ ∅ ) )
6 5 ineq1d ( 𝑠 = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) )
7 6 eqeq1d ( 𝑠 = ∅ → ( ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ↔ ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) )
8 4 7 imbi12d ( 𝑠 = ∅ → ( ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) ↔ ( ( ∅ ∩ 𝑡 ) = ∅ → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) ) )
9 0in ( ∅ ∩ 𝑡 ) = ∅
10 pm5.5 ( ( ∅ ∩ 𝑡 ) = ∅ → ( ( ( ∅ ∩ 𝑡 ) = ∅ → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) ↔ ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) )
11 9 10 ax-mp ( ( ( ∅ ∩ 𝑡 ) = ∅ → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) ↔ ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ )
12 8 11 syl6bb ( 𝑠 = ∅ → ( ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) ↔ ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ) )
13 fveq2 ( 𝑡 = ∅ → ( 𝐼𝑡 ) = ( 𝐼 ‘ ∅ ) )
14 13 ineq2d ( 𝑡 = ∅ → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼 ‘ ∅ ) ) )
15 14 eqeq1d ( 𝑡 = ∅ → ( ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼𝑡 ) ) = ∅ ↔ ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼 ‘ ∅ ) ) = ∅ ) )
16 12 15 rspc2v ( ( ∅ ∈ 𝒫 𝐵 ∧ ∅ ∈ 𝒫 𝐵 ) → ( ∀ 𝑠 ∈ 𝒫 𝐵𝑡 ∈ 𝒫 𝐵 ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼 ‘ ∅ ) ) = ∅ ) )
17 2 2 16 mp2an ( ∀ 𝑠 ∈ 𝒫 𝐵𝑡 ∈ 𝒫 𝐵 ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) → ( ( 𝐼 ‘ ∅ ) ∩ ( 𝐼 ‘ ∅ ) ) = ∅ )
18 1 17 syl5eqr ( ∀ 𝑠 ∈ 𝒫 𝐵𝑡 ∈ 𝒫 𝐵 ( ( 𝑠𝑡 ) = ∅ → ( ( 𝐼𝑠 ) ∩ ( 𝐼𝑡 ) ) = ∅ ) → ( 𝐼 ‘ ∅ ) = ∅ )