Metamath Proof Explorer


Theorem ofcfval4

Description: The function/constant operation expressed as an operation composition. (Contributed by Thierry Arnoux, 31-Jan-2017)

Ref Expression
Hypotheses ofcfval4.1 ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
ofcfval4.2 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
ofcfval4.3 ⊢ ( 𝜑 → 𝐶 ∈ 𝑊 )
Assertion ofcfval4 ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( ( 𝑥 ∈ 𝐵 ↦ ( 𝑥 𝑅 𝐶 ) ) ∘ 𝐹 ) )

Proof

Step Hyp Ref Expression
1 ofcfval4.1 ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
2 ofcfval4.2 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
3 ofcfval4.3 ⊢ ( 𝜑 → 𝐶 ∈ 𝑊 )
4 1 fdmd ⊢ ( 𝜑 → dom 𝐹 = 𝐴 )
5 4 mpteq1d ⊢ ( 𝜑 → ( 𝑦 ∈ dom 𝐹 ↦ ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) ) = ( 𝑦 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) ) )
6 1 2 fexd ⊢ ( 𝜑 → 𝐹 ∈ V )
7 ofcfval3 ⊢ ( ( 𝐹 ∈ V ∧ 𝐶 ∈ 𝑊 ) → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( 𝑦 ∈ dom 𝐹 ↦ ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) ) )
8 6 3 7 syl2anc ⊢ ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( 𝑦 ∈ dom 𝐹 ↦ ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) ) )
9 1 ffvelcdmda ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑦 ) ∈ 𝐵 )
10 1 feqmptd ⊢ ( 𝜑 → 𝐹 = ( 𝑦 ∈ 𝐴 ↦ ( 𝐹 ‘ 𝑦 ) ) )
11 eqidd ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐵 ↦ ( 𝑥 𝑅 𝐶 ) ) = ( 𝑥 ∈ 𝐵 ↦ ( 𝑥 𝑅 𝐶 ) ) )
12 oveq1 ⊢ ( 𝑥 = ( 𝐹 ‘ 𝑦 ) → ( 𝑥 𝑅 𝐶 ) = ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) )
13 9 10 11 12 fmptco ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐵 ↦ ( 𝑥 𝑅 𝐶 ) ) ∘ 𝐹 ) = ( 𝑦 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑦 ) 𝑅 𝐶 ) ) )
14 5 8 13 3eqtr4d ⊢ ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( ( 𝑥 ∈ 𝐵 ↦ ( 𝑥 𝑅 𝐶 ) ) ∘ 𝐹 ) )