Metamath Proof Explorer


Theorem qshash

Description: The cardinality of a set with an equivalence relation is the sum of the cardinalities of its equivalence classes. (Contributed by Mario Carneiro, 16-Jan-2015)

Ref Expression
Hypotheses qshash.1 ⊢ ( 𝜑 → ∼ Er 𝐴 )
qshash.2 ⊢ ( 𝜑 → 𝐴 ∈ Fin )
Assertion qshash ( 𝜑 → ( ♯ ‘ 𝐴 ) = Σ 𝑥 ∈ ( 𝐴 / ∼ ) ( ♯ ‘ 𝑥 ) )

Proof

Step Hyp Ref Expression
1 qshash.1 ⊢ ( 𝜑 → ∼ Er 𝐴 )
2 qshash.2 ⊢ ( 𝜑 → 𝐴 ∈ Fin )
3 erex ⊢ ( ∼ Er 𝐴 → ( 𝐴 ∈ Fin → ∼ ∈ V ) )
4 1 2 3 sylc ⊢ ( 𝜑 → ∼ ∈ V )
5 1 4 uniqs2 ⊢ ( 𝜑 → ∪ ( 𝐴 / ∼ ) = 𝐴 )
6 5 fveq2d ⊢ ( 𝜑 → ( ♯ ‘ ∪ ( 𝐴 / ∼ ) ) = ( ♯ ‘ 𝐴 ) )
7 pwfi ⊢ ( 𝐴 ∈ Fin ↔ 𝒫 𝐴 ∈ Fin )
8 2 7 sylib ⊢ ( 𝜑 → 𝒫 𝐴 ∈ Fin )
9 1 qsss ⊢ ( 𝜑 → ( 𝐴 / ∼ ) ⊆ 𝒫 𝐴 )
10 8 9 ssfid ⊢ ( 𝜑 → ( 𝐴 / ∼ ) ∈ Fin )
11 elpwi ⊢ ( 𝑥 ∈ 𝒫 𝐴 → 𝑥 ⊆ 𝐴 )
12 ssfi ⊢ ( ( 𝐴 ∈ Fin ∧ 𝑥 ⊆ 𝐴 ) → 𝑥 ∈ Fin )
13 12 ex ⊢ ( 𝐴 ∈ Fin → ( 𝑥 ⊆ 𝐴 → 𝑥 ∈ Fin ) )
14 2 11 13 syl2im ⊢ ( 𝜑 → ( 𝑥 ∈ 𝒫 𝐴 → 𝑥 ∈ Fin ) )
15 14 ssrdv ⊢ ( 𝜑 → 𝒫 𝐴 ⊆ Fin )
16 9 15 sstrd ⊢ ( 𝜑 → ( 𝐴 / ∼ ) ⊆ Fin )
17 qsdisj2 ⊢ ( ∼ Er 𝐴 → Disj 𝑥 ∈ ( 𝐴 / ∼ ) 𝑥 )
18 1 17 syl ⊢ ( 𝜑 → Disj 𝑥 ∈ ( 𝐴 / ∼ ) 𝑥 )
19 10 16 18 hashuni ⊢ ( 𝜑 → ( ♯ ‘ ∪ ( 𝐴 / ∼ ) ) = Σ 𝑥 ∈ ( 𝐴 / ∼ ) ( ♯ ‘ 𝑥 ) )
20 6 19 eqtr3d ⊢ ( 𝜑 → ( ♯ ‘ 𝐴 ) = Σ 𝑥 ∈ ( 𝐴 / ∼ ) ( ♯ ‘ 𝑥 ) )