Metamath Proof Explorer


Theorem swapf1a

Description: The object part of the swap functor swaps the objects. (Contributed by Zhi Wang, 7-Oct-2025)

Ref Expression
Hypotheses swapf1a.o ⊢ ( 𝜑 → ( 𝐶 swapF 𝐷 ) = ⟨ 𝑂 , 𝑃 ⟩ )
swapf1a.s ⊢ 𝑆 = ( 𝐶 ×c 𝐷 )
swapf1a.b ⊢ 𝐵 = ( Base ‘ 𝑆 )
swapf1a.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
Assertion swapf1a ( 𝜑 → ( 𝑂 ‘ 𝑋 ) = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )

Proof

Step Hyp Ref Expression
1 swapf1a.o ⊢ ( 𝜑 → ( 𝐶 swapF 𝐷 ) = ⟨ 𝑂 , 𝑃 ⟩ )
2 swapf1a.s ⊢ 𝑆 = ( 𝐶 ×c 𝐷 )
3 swapf1a.b ⊢ 𝐵 = ( Base ‘ 𝑆 )
4 swapf1a.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
5 2 3 4 elxpcbasex1 ⊢ ( 𝜑 → 𝐶 ∈ V )
6 2 3 4 elxpcbasex2 ⊢ ( 𝜑 → 𝐷 ∈ V )
7 5 6 2 3 1 swapf1val ⊢ ( 𝜑 → 𝑂 = ( 𝑥 ∈ 𝐵 ↦ ∪ ◡ { 𝑥 } ) )
8 simpr ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → 𝑥 = 𝑋 )
9 8 sneqd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → { 𝑥 } = { 𝑋 } )
10 9 cnveqd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → ◡ { 𝑥 } = ◡ { 𝑋 } )
11 10 unieqd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → ∪ ◡ { 𝑥 } = ∪ ◡ { 𝑋 } )
12 eqid ⊢ ( Base ‘ 𝐶 ) = ( Base ‘ 𝐶 )
13 eqid ⊢ ( Base ‘ 𝐷 ) = ( Base ‘ 𝐷 )
14 2 12 13 xpcbas ⊢ ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) = ( Base ‘ 𝑆 )
15 3 14 eqtr4i ⊢ 𝐵 = ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) )
16 4 15 eleqtrdi ⊢ ( 𝜑 → 𝑋 ∈ ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) )
17 2nd1st ⊢ ( 𝑋 ∈ ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) → ∪ ◡ { 𝑋 } = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )
18 16 17 syl ⊢ ( 𝜑 → ∪ ◡ { 𝑋 } = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )
19 18 adantr ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → ∪ ◡ { 𝑋 } = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )
20 11 19 eqtrd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑋 ) → ∪ ◡ { 𝑥 } = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )
21 opex ⊢ ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ ∈ V
22 21 a1i ⊢ ( 𝜑 → ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ ∈ V )
23 7 20 4 22 fvmptd ⊢ ( 𝜑 → ( 𝑂 ‘ 𝑋 ) = ⟨ ( 2nd ‘ 𝑋 ) , ( 1st ‘ 𝑋 ) ⟩ )