Metamath Proof Explorer


Theorem swapf1a

Description: The object part of the swap functor swaps the objects. (Contributed by Zhi Wang, 7-Oct-2025)

Ref Expression
Hypotheses swapf1a.o ( 𝜑 → ( 𝐶 swapF 𝐷 ) = ⟨ 𝑂 , 𝑃 ⟩ )
swapf1a.s 𝑆 = ( 𝐶 ×c 𝐷 )
swapf1a.b 𝐵 = ( Base ‘ 𝑆 )
swapf1a.x ( 𝜑𝑋𝐵 )
Assertion swapf1a ( 𝜑 → ( 𝑂𝑋 ) = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )

Proof

Step Hyp Ref Expression
1 swapf1a.o ( 𝜑 → ( 𝐶 swapF 𝐷 ) = ⟨ 𝑂 , 𝑃 ⟩ )
2 swapf1a.s 𝑆 = ( 𝐶 ×c 𝐷 )
3 swapf1a.b 𝐵 = ( Base ‘ 𝑆 )
4 swapf1a.x ( 𝜑𝑋𝐵 )
5 2 3 4 elxpcbasex1 ( 𝜑𝐶 ∈ V )
6 2 3 4 elxpcbasex2 ( 𝜑𝐷 ∈ V )
7 5 6 2 3 1 swapf1val ( 𝜑𝑂 = ( 𝑥𝐵 { 𝑥 } ) )
8 simpr ( ( 𝜑𝑥 = 𝑋 ) → 𝑥 = 𝑋 )
9 8 sneqd ( ( 𝜑𝑥 = 𝑋 ) → { 𝑥 } = { 𝑋 } )
10 9 cnveqd ( ( 𝜑𝑥 = 𝑋 ) → { 𝑥 } = { 𝑋 } )
11 10 unieqd ( ( 𝜑𝑥 = 𝑋 ) → { 𝑥 } = { 𝑋 } )
12 eqid ( Base ‘ 𝐶 ) = ( Base ‘ 𝐶 )
13 eqid ( Base ‘ 𝐷 ) = ( Base ‘ 𝐷 )
14 2 12 13 xpcbas ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) = ( Base ‘ 𝑆 )
15 3 14 eqtr4i 𝐵 = ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) )
16 4 15 eleqtrdi ( 𝜑𝑋 ∈ ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) )
17 2nd1st ( 𝑋 ∈ ( ( Base ‘ 𝐶 ) × ( Base ‘ 𝐷 ) ) → { 𝑋 } = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )
18 16 17 syl ( 𝜑 { 𝑋 } = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )
19 18 adantr ( ( 𝜑𝑥 = 𝑋 ) → { 𝑋 } = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )
20 11 19 eqtrd ( ( 𝜑𝑥 = 𝑋 ) → { 𝑥 } = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )
21 opex ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ ∈ V
22 21 a1i ( 𝜑 → ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ ∈ V )
23 7 20 4 22 fvmptd ( 𝜑 → ( 𝑂𝑋 ) = ⟨ ( 2nd𝑋 ) , ( 1st𝑋 ) ⟩ )