Metamath Proof Explorer


Theorem zcuts0

Description: Either the left or right set of a surreal integer is empty. (Contributed by Scott Fenton, 21-Feb-2026)

Ref Expression
Assertion zcuts0 ( 𝐴 ∈ ℤs → ( ( L ‘ 𝐴 ) = ∅ ∨ ( R ‘ 𝐴 ) = ∅ ) )

Proof

Step Hyp Ref Expression
1 elzn0s ⊢ ( 𝐴 ∈ ℤs ↔ ( 𝐴 ∈ No ∧ ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) ) )
2 n0on ⊢ ( 𝐴 ∈ ℕ0s → 𝐴 ∈ Ons )
3 elons ⊢ ( 𝐴 ∈ Ons ↔ ( 𝐴 ∈ No ∧ ( R ‘ 𝐴 ) = ∅ ) )
4 3 simprbi ⊢ ( 𝐴 ∈ Ons → ( R ‘ 𝐴 ) = ∅ )
5 2 4 syl ⊢ ( 𝐴 ∈ ℕ0s → ( R ‘ 𝐴 ) = ∅ )
6 5 a1i ⊢ ( 𝐴 ∈ No → ( 𝐴 ∈ ℕ0s → ( R ‘ 𝐴 ) = ∅ ) )
7 simpl ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → 𝐴 ∈ No )
8 7 negscld ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( -us ‘ 𝐴 ) ∈ No )
9 negleft ⊢ ( ( -us ‘ 𝐴 ) ∈ No → ( L ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) = ( -us “ ( R ‘ ( -us ‘ 𝐴 ) ) ) )
10 8 9 syl ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( L ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) = ( -us “ ( R ‘ ( -us ‘ 𝐴 ) ) ) )
11 negnegs ⊢ ( 𝐴 ∈ No → ( -us ‘ ( -us ‘ 𝐴 ) ) = 𝐴 )
12 11 fveq2d ⊢ ( 𝐴 ∈ No → ( L ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) = ( L ‘ 𝐴 ) )
13 12 adantr ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( L ‘ ( -us ‘ ( -us ‘ 𝐴 ) ) ) = ( L ‘ 𝐴 ) )
14 n0on ⊢ ( ( -us ‘ 𝐴 ) ∈ ℕ0s → ( -us ‘ 𝐴 ) ∈ Ons )
15 elons ⊢ ( ( -us ‘ 𝐴 ) ∈ Ons ↔ ( ( -us ‘ 𝐴 ) ∈ No ∧ ( R ‘ ( -us ‘ 𝐴 ) ) = ∅ ) )
16 15 simprbi ⊢ ( ( -us ‘ 𝐴 ) ∈ Ons → ( R ‘ ( -us ‘ 𝐴 ) ) = ∅ )
17 14 16 syl ⊢ ( ( -us ‘ 𝐴 ) ∈ ℕ0s → ( R ‘ ( -us ‘ 𝐴 ) ) = ∅ )
18 17 adantl ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( R ‘ ( -us ‘ 𝐴 ) ) = ∅ )
19 18 imaeq2d ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( -us “ ( R ‘ ( -us ‘ 𝐴 ) ) ) = ( -us “ ∅ ) )
20 ima0 ⊢ ( -us “ ∅ ) = ∅
21 19 20 eqtrdi ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( -us “ ( R ‘ ( -us ‘ 𝐴 ) ) ) = ∅ )
22 10 13 21 3eqtr3d ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( L ‘ 𝐴 ) = ∅ )
23 22 ex ⊢ ( 𝐴 ∈ No → ( ( -us ‘ 𝐴 ) ∈ ℕ0s → ( L ‘ 𝐴 ) = ∅ ) )
24 6 23 orim12d ⊢ ( 𝐴 ∈ No → ( ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( ( R ‘ 𝐴 ) = ∅ ∨ ( L ‘ 𝐴 ) = ∅ ) ) )
25 24 imp ⊢ ( ( 𝐴 ∈ No ∧ ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) ) → ( ( R ‘ 𝐴 ) = ∅ ∨ ( L ‘ 𝐴 ) = ∅ ) )
26 25 orcomd ⊢ ( ( 𝐴 ∈ No ∧ ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) ) → ( ( L ‘ 𝐴 ) = ∅ ∨ ( R ‘ 𝐴 ) = ∅ ) )
27 1 26 sylbi ⊢ ( 𝐴 ∈ ℤs → ( ( L ‘ 𝐴 ) = ∅ ∨ ( R ‘ 𝐴 ) = ∅ ) )