Metamath Proof Explorer


Theorem 0ringmon1p

Description: There are no monic polynomials over a zero ring. (Contributed by Thierry Arnoux, 5-Feb-2025)

Ref Expression
Hypotheses 0ringmon1p.1 ⊢ M = Monic 1p ⁡ R
0ringmon1p.2 ⊢ B = Base R
0ringmon1p.3 ⊢ φ → R ∈ Ring
0ringmon1p.4 ⊢ φ → B = 1
Assertion 0ringmon1p ⊢ φ → M = ∅

Proof

Step Hyp Ref Expression
1 0ringmon1p.1 ⊢ M = Monic 1p ⁡ R
2 0ringmon1p.2 ⊢ B = Base R
3 0ringmon1p.3 ⊢ φ → R ∈ Ring
4 0ringmon1p.4 ⊢ φ → B = 1
5 eqid ⊢ Poly 1 ⁡ R = Poly 1 ⁡ R
6 eqid ⊢ Base Poly 1 ⁡ R = Base Poly 1 ⁡ R
7 eqid ⊢ 0 Poly 1 ⁡ R = 0 Poly 1 ⁡ R
8 eqid ⊢ deg 1 ⁡ R = deg 1 ⁡ R
9 eqid ⊢ 1 R = 1 R
10 5 6 7 8 1 9 ismon1p ⊢ p ∈ M ↔ p ∈ Base Poly 1 ⁡ R ∧ p ≠ 0 Poly 1 ⁡ R ∧ coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p = 1 R
11 10 bilani ⊢ φ ∧ p ∈ M → p ∈ Base Poly 1 ⁡ R ∧ p ≠ 0 Poly 1 ⁡ R ∧ coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p = 1 R
12 11 simp3d ⊢ φ ∧ p ∈ M → coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p = 1 R
13 3 adantr ⊢ φ ∧ p ∈ M → R ∈ Ring
14 11 simp1d ⊢ φ ∧ p ∈ M → p ∈ Base Poly 1 ⁡ R
15 11 simp2d ⊢ φ ∧ p ∈ M → p ≠ 0 Poly 1 ⁡ R
16 eqid ⊢ 0 R = 0 R
17 eqid ⊢ coe 1 ⁡ p = coe 1 ⁡ p
18 8 5 7 6 16 17 deg1ldg ⊢ R ∈ Ring ∧ p ∈ Base Poly 1 ⁡ R ∧ p ≠ 0 Poly 1 ⁡ R → coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p ≠ 0 R
19 13 14 15 18 syl3anc ⊢ φ ∧ p ∈ M → coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p ≠ 0 R
20 2 16 9 0ring01eq ⊢ R ∈ Ring ∧ B = 1 → 0 R = 1 R
21 3 4 20 syl2anc ⊢ φ → 0 R = 1 R
22 21 adantr ⊢ φ ∧ p ∈ M → 0 R = 1 R
23 19 22 neeqtrd ⊢ φ ∧ p ∈ M → coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p ≠ 1 R
24 23 neneqd ⊢ φ ∧ p ∈ M → ¬ coe 1 ⁡ p ⁡ deg 1 ⁡ R ⁡ p = 1 R
25 12 24 pm2.65da ⊢ φ → ¬ p ∈ M
26 25 eq0rdv ⊢ φ → M = ∅