Metamath Proof Explorer


Theorem 1stcof

Description: Composition of the first member function with another function. (Contributed by NM, 12-Oct-2007)

Ref Expression
Assertion 1stcof ⊢ F : A ⟶ B × C → 1 st ∘ F : A ⟶ B

Proof

Step Hyp Ref Expression
1 fo1st ⊢ 1 st : V ⟶ onto V
2 fofn ⊢ 1 st : V ⟶ onto V → 1 st Fn V
3 1 2 ax-mp ⊢ 1 st Fn V
4 ffn ⊢ F : A ⟶ B × C → F Fn A
5 dffn2 ⊢ F Fn A ↔ F : A ⟶ V
6 4 5 sylib ⊢ F : A ⟶ B × C → F : A ⟶ V
7 fnfco ⊢ 1 st Fn V ∧ F : A ⟶ V → 1 st ∘ F Fn A
8 3 6 7 sylancr ⊢ F : A ⟶ B × C → 1 st ∘ F Fn A
9 rnco ⊢ ran ⁡ 1 st ∘ F = ran ⁡ 1 st ↾ ran ⁡ F
10 frn ⊢ F : A ⟶ B × C → ran ⁡ F ⊆ B × C
11 ssres2 ⊢ ran ⁡ F ⊆ B × C → 1 st ↾ ran ⁡ F ⊆ 1 st ↾ B × C
12 rnss ⊢ 1 st ↾ ran ⁡ F ⊆ 1 st ↾ B × C → ran ⁡ 1 st ↾ ran ⁡ F ⊆ ran ⁡ 1 st ↾ B × C
13 10 11 12 3syl ⊢ F : A ⟶ B × C → ran ⁡ 1 st ↾ ran ⁡ F ⊆ ran ⁡ 1 st ↾ B × C
14 f1stres ⊢ 1 st ↾ B × C : B × C ⟶ B
15 frn ⊢ 1 st ↾ B × C : B × C ⟶ B → ran ⁡ 1 st ↾ B × C ⊆ B
16 14 15 ax-mp ⊢ ran ⁡ 1 st ↾ B × C ⊆ B
17 13 16 sstrdi ⊢ F : A ⟶ B × C → ran ⁡ 1 st ↾ ran ⁡ F ⊆ B
18 9 17 eqsstrid ⊢ F : A ⟶ B × C → ran ⁡ 1 st ∘ F ⊆ B
19 df-f ⊢ 1 st ∘ F : A ⟶ B ↔ 1 st ∘ F Fn A ∧ ran ⁡ 1 st ∘ F ⊆ B
20 8 18 19 sylanbrc ⊢ F : A ⟶ B × C → 1 st ∘ F : A ⟶ B