Metamath Proof Explorer


Theorem 2sphere0

Description: The sphere around the origin .0. (see rrx0 ) with radius R in a two dimensional Euclidean space is a circle. (Contributed by AV, 5-Feb-2023)

Ref Expression
Hypotheses 2sphere.i ⊢ I = 1 2
2sphere.e ⊢ E = I
2sphere.p ⊢ P = ℝ I
2sphere.s ⊢ S = Sphere ⁡ E
2sphere0.0 ⊢ 0 ˙ = I × 0
2sphere0.c ⊢ C = p ∈ P | p ⁡ 1 2 + p ⁡ 2 2 = R 2
Assertion 2sphere0 ⊢ R ∈ 0 +∞ → 0 ˙ S R = C

Proof

Step Hyp Ref Expression
1 2sphere.i ⊢ I = 1 2
2 2sphere.e ⊢ E = I
3 2sphere.p ⊢ P = ℝ I
4 2sphere.s ⊢ S = Sphere ⁡ E
5 2sphere0.0 ⊢ 0 ˙ = I × 0
6 2sphere0.c ⊢ C = p ∈ P | p ⁡ 1 2 + p ⁡ 2 2 = R 2
7 prex ⊢ 1 2 ∈ V
8 1 7 eqeltri ⊢ I ∈ V
9 5 3 rrx0el ⊢ I ∈ V → 0 ˙ ∈ P
10 8 9 ax-mp ⊢ 0 ˙ ∈ P
11 eqid ⊢ p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2 = p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2
12 1 2 3 4 11 2sphere ⊢ 0 ˙ ∈ P ∧ R ∈ 0 +∞ → 0 ˙ S R = p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2
13 10 12 mpan ⊢ R ∈ 0 +∞ → 0 ˙ S R = p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2
14 5 fveq1i ⊢ 0 ˙ ⁡ 1 = I × 0 ⁡ 1
15 c0ex ⊢ 0 ∈ V
16 1ex ⊢ 1 ∈ V
17 16 prid1 ⊢ 1 ∈ 1 2
18 17 1 eleqtrri ⊢ 1 ∈ I
19 fvconst2g ⊢ 0 ∈ V ∧ 1 ∈ I → I × 0 ⁡ 1 = 0
20 15 18 19 mp2an ⊢ I × 0 ⁡ 1 = 0
21 14 20 eqtri ⊢ 0 ˙ ⁡ 1 = 0
22 21 a1i ⊢ p ∈ P → 0 ˙ ⁡ 1 = 0
23 22 oveq2d ⊢ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 = p ⁡ 1 − 0
24 1 3 rrx2pxel ⊢ p ∈ P → p ⁡ 1 ∈ ℝ
25 24 recnd ⊢ p ∈ P → p ⁡ 1 ∈ ℂ
26 25 subid1d ⊢ p ∈ P → p ⁡ 1 − 0 = p ⁡ 1
27 23 26 eqtrd ⊢ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 = p ⁡ 1
28 27 oveq1d ⊢ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 2 = p ⁡ 1 2
29 5 fveq1i ⊢ 0 ˙ ⁡ 2 = I × 0 ⁡ 2
30 2ex ⊢ 2 ∈ V
31 30 prid2 ⊢ 2 ∈ 1 2
32 31 1 eleqtrri ⊢ 2 ∈ I
33 fvconst2g ⊢ 0 ∈ V ∧ 2 ∈ I → I × 0 ⁡ 2 = 0
34 15 32 33 mp2an ⊢ I × 0 ⁡ 2 = 0
35 29 34 eqtri ⊢ 0 ˙ ⁡ 2 = 0
36 35 a1i ⊢ p ∈ P → 0 ˙ ⁡ 2 = 0
37 36 oveq2d ⊢ p ∈ P → p ⁡ 2 − 0 ˙ ⁡ 2 = p ⁡ 2 − 0
38 1 3 rrx2pyel ⊢ p ∈ P → p ⁡ 2 ∈ ℝ
39 38 recnd ⊢ p ∈ P → p ⁡ 2 ∈ ℂ
40 39 subid1d ⊢ p ∈ P → p ⁡ 2 − 0 = p ⁡ 2
41 37 40 eqtrd ⊢ p ∈ P → p ⁡ 2 − 0 ˙ ⁡ 2 = p ⁡ 2
42 41 oveq1d ⊢ p ∈ P → p ⁡ 2 − 0 ˙ ⁡ 2 2 = p ⁡ 2 2
43 28 42 oveq12d ⊢ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = p ⁡ 1 2 + p ⁡ 2 2
44 43 eqeq1d ⊢ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2 ↔ p ⁡ 1 2 + p ⁡ 2 2 = R 2
45 44 adantl ⊢ R ∈ 0 +∞ ∧ p ∈ P → p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2 ↔ p ⁡ 1 2 + p ⁡ 2 2 = R 2
46 45 rabbidva ⊢ R ∈ 0 +∞ → p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2 = p ∈ P | p ⁡ 1 2 + p ⁡ 2 2 = R 2
47 46 6 eqtr4di ⊢ R ∈ 0 +∞ → p ∈ P | p ⁡ 1 − 0 ˙ ⁡ 1 2 + p ⁡ 2 − 0 ˙ ⁡ 2 2 = R 2 = C
48 13 47 eqtrd ⊢ R ∈ 0 +∞ → 0 ˙ S R = C