Metamath Proof Explorer


Theorem cbvitgdavw2

Description: Change bound variable and domain in an integral. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypotheses cbvitgdavw2.1 ⊢ φ ∧ x = y → C = D
cbvitgdavw2.2 ⊢ φ ∧ x = y → A = B
Assertion cbvitgdavw2 ⊢ φ → ∫ A C dx = ∫ B D dy

Proof

Step Hyp Ref Expression
1 cbvitgdavw2.1 ⊢ φ ∧ x = y → C = D
2 cbvitgdavw2.2 ⊢ φ ∧ x = y → A = B
3 1 fvoveq1d ⊢ φ ∧ x = y → ℜ ⁡ C i t = ℜ ⁡ D i t
4 simpr ⊢ φ ∧ x = y → x = y
5 4 2 eleq12d ⊢ φ ∧ x = y → x ∈ A ↔ y ∈ B
6 5 anbi1d ⊢ φ ∧ x = y → x ∈ A ∧ 0 ≤ v ↔ y ∈ B ∧ 0 ≤ v
7 6 ifbid ⊢ φ ∧ x = y → if x ∈ A ∧ 0 ≤ v v 0 = if y ∈ B ∧ 0 ≤ v v 0
8 3 7 csbeq12dv ⊢ φ ∧ x = y → ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0 = ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
9 8 cbvmptdavw ⊢ φ → x ∈ ℝ ⟼ ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0 = y ∈ ℝ ⟼ ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
10 9 fveq2d ⊢ φ → ∫ 2 ⁡ x ∈ ℝ ⟼ ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0 = ∫ 2 ⁡ y ∈ ℝ ⟼ ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
11 10 oveq2d ⊢ φ → i t ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0 = i t ⁢ ∫ 2 ⁡ y ∈ ℝ ⟼ ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
12 11 sumeq2sdv ⊢ φ → ∑ t = 0 3 i t ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0 = ∑ t = 0 3 i t ⁢ ∫ 2 ⁡ y ∈ ℝ ⟼ ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
13 df-itg ⊢ ∫ A C dx = ∑ t = 0 3 i t ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ ⦋ ℜ ⁡ C i t / v⦌ if x ∈ A ∧ 0 ≤ v v 0
14 df-itg ⊢ ∫ B D dy = ∑ t = 0 3 i t ⁢ ∫ 2 ⁡ y ∈ ℝ ⟼ ⦋ ℜ ⁡ D i t / v⦌ if y ∈ B ∧ 0 ≤ v v 0
15 12 13 14 3eqtr4g ⊢ φ → ∫ A C dx = ∫ B D dy