Metamath Proof Explorer


Theorem cdlemkid

Description: The value of the tau function (in Lemma K of Crawley p. 118) on the identity relation. (Contributed by NM, 25-Jul-2013)

Ref Expression
Hypotheses cdlemk5.b ⊢ B = Base K
cdlemk5.l ⊢ ≤ ˙ = ≤ K
cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
cdlemk5.a ⊢ A = Atoms ⁡ K
cdlemk5.h ⊢ H = LHyp ⁡ K
cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
Assertion cdlemkid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → ⦋ G / g⦌ X = I ↾ B

Proof

Step Hyp Ref Expression
1 cdlemk5.b ⊢ B = Base K
2 cdlemk5.l ⊢ ≤ ˙ = ≤ K
3 cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemk5.a ⊢ A = Atoms ⁡ K
6 cdlemk5.h ⊢ H = LHyp ⁡ K
7 cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
9 cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
10 cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
11 cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
12 7 fvexi ⊢ T ∈ V
13 nfv ⊢ Ⅎ b K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B
14 nfcv ⊢ Ⅎ _ b G
15 nfra1 ⊢ Ⅎ b ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
16 nfcv ⊢ Ⅎ _ b T
17 15 16 nfriota ⊢ Ⅎ _ b ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
18 11 17 nfcxfr ⊢ Ⅎ _ b X
19 14 18 nfcsbw ⊢ Ⅎ _ b ⦋ G / g⦌ X
20 19 nfeq1 ⊢ Ⅎ b ⦋ G / g⦌ X = I ↾ B
21 20 a1i ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → Ⅎ b ⦋ G / g⦌ X = I ↾ B
22 1 2 3 4 5 6 7 8 9 10 11 cdlemkid4 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → ⦋ G / g⦌ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ G → z = I ↾ B
23 eqeq1 ⊢ I ↾ B = ⦋ G / g⦌ X → I ↾ B = I ↾ B ↔ ⦋ G / g⦌ X = I ↾ B
24 23 adantl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B ∧ I ↾ B = ⦋ G / g⦌ X → I ↾ B = I ↾ B ↔ ⦋ G / g⦌ X = I ↾ B
25 eqidd ⊢ b ∈ T ∧ b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ G → I ↾ B = I ↾ B
26 25 a1i ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → b ∈ T ∧ b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ G → I ↾ B = I ↾ B
27 1 2 3 4 5 6 7 8 9 10 11 cdlemkid5 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → ⦋ G / g⦌ X ∈ T
28 1 6 7 8 cdlemftr2 ⊢ K ∈ HL ∧ W ∈ H → ∃ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ G
29 28 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → ∃ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ G
30 13 21 22 24 26 27 29 riotasv3d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B ∧ T ∈ V → ⦋ G / g⦌ X = I ↾ B
31 12 30 mpan2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G = I ↾ B → ⦋ G / g⦌ X = I ↾ B