Metamath Proof Explorer


Theorem cos2tsin

Description: Double-angle formula for cosine in terms of sine. (Contributed by NM, 12-Sep-2008)

Ref Expression
Assertion cos2tsin ⊢ A ∈ ℂ → cos ⁡ 2 ⁢ A = 1 − 2 ⁢ sin ⁡ A 2

Proof

Step Hyp Ref Expression
1 cos2t ⊢ A ∈ ℂ → cos ⁡ 2 ⁢ A = 2 ⁢ cos ⁡ A 2 − 1
2 2cn ⊢ 2 ∈ ℂ
3 sincl ⊢ A ∈ ℂ → sin ⁡ A ∈ ℂ
4 3 sqcld ⊢ A ∈ ℂ → sin ⁡ A 2 ∈ ℂ
5 coscl ⊢ A ∈ ℂ → cos ⁡ A ∈ ℂ
6 5 sqcld ⊢ A ∈ ℂ → cos ⁡ A 2 ∈ ℂ
7 adddi ⊢ 2 ∈ ℂ ∧ sin ⁡ A 2 ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ → 2 ⁢ sin ⁡ A 2 + cos ⁡ A 2 = 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2
8 2 4 6 7 mp3an2i ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 + cos ⁡ A 2 = 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2
9 sincossq ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = 1
10 9 oveq2d ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 + cos ⁡ A 2 = 2 ⋅ 1
11 8 10 eqtr3d ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2 = 2 ⋅ 1
12 2t1e2 ⊢ 2 ⋅ 1 = 2
13 11 12 eqtrdi ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2 = 2
14 mulcl ⊢ 2 ∈ ℂ ∧ sin ⁡ A 2 ∈ ℂ → 2 ⁢ sin ⁡ A 2 ∈ ℂ
15 2 4 14 sylancr ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 ∈ ℂ
16 mulcl ⊢ 2 ∈ ℂ ∧ cos ⁡ A 2 ∈ ℂ → 2 ⁢ cos ⁡ A 2 ∈ ℂ
17 2 6 16 sylancr ⊢ A ∈ ℂ → 2 ⁢ cos ⁡ A 2 ∈ ℂ
18 subadd ⊢ 2 ∈ ℂ ∧ 2 ⁢ sin ⁡ A 2 ∈ ℂ ∧ 2 ⁢ cos ⁡ A 2 ∈ ℂ → 2 − 2 ⁢ sin ⁡ A 2 = 2 ⁢ cos ⁡ A 2 ↔ 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2 = 2
19 2 15 17 18 mp3an2i ⊢ A ∈ ℂ → 2 − 2 ⁢ sin ⁡ A 2 = 2 ⁢ cos ⁡ A 2 ↔ 2 ⁢ sin ⁡ A 2 + 2 ⁢ cos ⁡ A 2 = 2
20 13 19 mpbird ⊢ A ∈ ℂ → 2 − 2 ⁢ sin ⁡ A 2 = 2 ⁢ cos ⁡ A 2
21 20 oveq1d ⊢ A ∈ ℂ → 2 - 2 ⁢ sin ⁡ A 2 - 1 = 2 ⁢ cos ⁡ A 2 − 1
22 ax-1cn ⊢ 1 ∈ ℂ
23 sub32 ⊢ 2 ∈ ℂ ∧ 2 ⁢ sin ⁡ A 2 ∈ ℂ ∧ 1 ∈ ℂ → 2 - 2 ⁢ sin ⁡ A 2 - 1 = 2 - 1 - 2 ⁢ sin ⁡ A 2
24 2 22 23 mp3an13 ⊢ 2 ⁢ sin ⁡ A 2 ∈ ℂ → 2 - 2 ⁢ sin ⁡ A 2 - 1 = 2 - 1 - 2 ⁢ sin ⁡ A 2
25 15 24 syl ⊢ A ∈ ℂ → 2 - 2 ⁢ sin ⁡ A 2 - 1 = 2 - 1 - 2 ⁢ sin ⁡ A 2
26 2m1e1 ⊢ 2 − 1 = 1
27 26 oveq1i ⊢ 2 - 1 - 2 ⁢ sin ⁡ A 2 = 1 − 2 ⁢ sin ⁡ A 2
28 25 27 eqtrdi ⊢ A ∈ ℂ → 2 - 2 ⁢ sin ⁡ A 2 - 1 = 1 − 2 ⁢ sin ⁡ A 2
29 1 21 28 3eqtr2d ⊢ A ∈ ℂ → cos ⁡ 2 ⁢ A = 1 − 2 ⁢ sin ⁡ A 2