Metamath Proof Explorer


Theorem sincossq

Description: Sine squared plus cosine squared is 1. Equation 17 of Gleason p. 311. Note that this holds for non-real arguments, even though individually each term is unbounded. (Contributed by NM, 15-Jan-2006)

Ref Expression
Assertion sincossq ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = 1

Proof

Step Hyp Ref Expression
1 negcl ⊢ A ∈ ℂ → − A ∈ ℂ
2 cosadd ⊢ A ∈ ℂ ∧ − A ∈ ℂ → cos ⁡ A + − A = cos ⁡ A ⁢ cos ⁡ − A − sin ⁡ A ⁢ sin ⁡ − A
3 1 2 mpdan ⊢ A ∈ ℂ → cos ⁡ A + − A = cos ⁡ A ⁢ cos ⁡ − A − sin ⁡ A ⁢ sin ⁡ − A
4 negid ⊢ A ∈ ℂ → A + − A = 0
5 4 fveq2d ⊢ A ∈ ℂ → cos ⁡ A + − A = cos ⁡ 0
6 cos0 ⊢ cos ⁡ 0 = 1
7 5 6 eqtrdi ⊢ A ∈ ℂ → cos ⁡ A + − A = 1
8 sincl ⊢ A ∈ ℂ → sin ⁡ A ∈ ℂ
9 8 sqcld ⊢ A ∈ ℂ → sin ⁡ A 2 ∈ ℂ
10 coscl ⊢ A ∈ ℂ → cos ⁡ A ∈ ℂ
11 10 sqcld ⊢ A ∈ ℂ → cos ⁡ A 2 ∈ ℂ
12 9 11 addcomd ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = cos ⁡ A 2 + sin ⁡ A 2
13 10 sqvald ⊢ A ∈ ℂ → cos ⁡ A 2 = cos ⁡ A ⁢ cos ⁡ A
14 cosneg ⊢ A ∈ ℂ → cos ⁡ − A = cos ⁡ A
15 14 oveq2d ⊢ A ∈ ℂ → cos ⁡ A ⁢ cos ⁡ − A = cos ⁡ A ⁢ cos ⁡ A
16 13 15 eqtr4d ⊢ A ∈ ℂ → cos ⁡ A 2 = cos ⁡ A ⁢ cos ⁡ − A
17 8 sqvald ⊢ A ∈ ℂ → sin ⁡ A 2 = sin ⁡ A ⁢ sin ⁡ A
18 sinneg ⊢ A ∈ ℂ → sin ⁡ − A = − sin ⁡ A
19 18 negeqd ⊢ A ∈ ℂ → − sin ⁡ − A = − − sin ⁡ A
20 8 negnegd ⊢ A ∈ ℂ → − − sin ⁡ A = sin ⁡ A
21 19 20 eqtrd ⊢ A ∈ ℂ → − sin ⁡ − A = sin ⁡ A
22 21 oveq2d ⊢ A ∈ ℂ → sin ⁡ A ⁢ − sin ⁡ − A = sin ⁡ A ⁢ sin ⁡ A
23 17 22 eqtr4d ⊢ A ∈ ℂ → sin ⁡ A 2 = sin ⁡ A ⁢ − sin ⁡ − A
24 1 sincld ⊢ A ∈ ℂ → sin ⁡ − A ∈ ℂ
25 8 24 mulneg2d ⊢ A ∈ ℂ → sin ⁡ A ⁢ − sin ⁡ − A = − sin ⁡ A ⁢ sin ⁡ − A
26 23 25 eqtrd ⊢ A ∈ ℂ → sin ⁡ A 2 = − sin ⁡ A ⁢ sin ⁡ − A
27 16 26 oveq12d ⊢ A ∈ ℂ → cos ⁡ A 2 + sin ⁡ A 2 = cos ⁡ A ⁢ cos ⁡ − A + − sin ⁡ A ⁢ sin ⁡ − A
28 1 coscld ⊢ A ∈ ℂ → cos ⁡ − A ∈ ℂ
29 10 28 mulcld ⊢ A ∈ ℂ → cos ⁡ A ⁢ cos ⁡ − A ∈ ℂ
30 8 24 mulcld ⊢ A ∈ ℂ → sin ⁡ A ⁢ sin ⁡ − A ∈ ℂ
31 29 30 negsubd ⊢ A ∈ ℂ → cos ⁡ A ⁢ cos ⁡ − A + − sin ⁡ A ⁢ sin ⁡ − A = cos ⁡ A ⁢ cos ⁡ − A − sin ⁡ A ⁢ sin ⁡ − A
32 12 27 31 3eqtrrd ⊢ A ∈ ℂ → cos ⁡ A ⁢ cos ⁡ − A − sin ⁡ A ⁢ sin ⁡ − A = sin ⁡ A 2 + cos ⁡ A 2
33 3 7 32 3eqtr3rd ⊢ A ∈ ℂ → sin ⁡ A 2 + cos ⁡ A 2 = 1