Metamath Proof Explorer


Theorem dipassr

Description: "Associative" law for second argument of inner product (compare dipass ). (Contributed by NM, 22-Nov-2007) (New usage is discouraged.)

Ref Expression
Hypotheses ipass.1 ⊢ X = BaseSet ⁡ U
ipass.4 ⊢ S = ⋅ 𝑠OLD ⁡ U
ipass.7 ⊢ P = ⋅ 𝑖OLD ⁡ U
Assertion dipassr ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → A P B S C = B ‾ ⁢ A P C

Proof

Step Hyp Ref Expression
1 ipass.1 ⊢ X = BaseSet ⁡ U
2 ipass.4 ⊢ S = ⋅ 𝑠OLD ⁡ U
3 ipass.7 ⊢ P = ⋅ 𝑖OLD ⁡ U
4 3anrot ⊢ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X ↔ B ∈ ℂ ∧ C ∈ X ∧ A ∈ X
5 1 2 3 dipass ⊢ U ∈ CPreHil OLD ∧ B ∈ ℂ ∧ C ∈ X ∧ A ∈ X → B S C P A = B ⁢ C P A
6 4 5 sylan2b ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B S C P A = B ⁢ C P A
7 6 fveq2d ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B S C P A ‾ = B ⁢ C P A ‾
8 phnv ⊢ U ∈ CPreHil OLD → U ∈ NrmCVec
9 simpl ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → U ∈ NrmCVec
10 1 2 nvscl ⊢ U ∈ NrmCVec ∧ B ∈ ℂ ∧ C ∈ X → B S C ∈ X
11 10 3adant3r1 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B S C ∈ X
12 simpr1 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → A ∈ X
13 1 3 dipcj ⊢ U ∈ NrmCVec ∧ B S C ∈ X ∧ A ∈ X → B S C P A ‾ = A P B S C
14 9 11 12 13 syl3anc ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B S C P A ‾ = A P B S C
15 8 14 sylan ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B S C P A ‾ = A P B S C
16 simpr2 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B ∈ ℂ
17 1 3 dipcl ⊢ U ∈ NrmCVec ∧ C ∈ X ∧ A ∈ X → C P A ∈ ℂ
18 17 3com23 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ C ∈ X → C P A ∈ ℂ
19 18 3adant3r2 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → C P A ∈ ℂ
20 16 19 cjmuld ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B ⁢ C P A ‾ = B ‾ ⁢ C P A ‾
21 1 3 dipcj ⊢ U ∈ NrmCVec ∧ C ∈ X ∧ A ∈ X → C P A ‾ = A P C
22 21 3com23 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ C ∈ X → C P A ‾ = A P C
23 22 3adant3r2 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → C P A ‾ = A P C
24 23 oveq2d ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B ‾ ⁢ C P A ‾ = B ‾ ⁢ A P C
25 20 24 eqtrd ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B ⁢ C P A ‾ = B ‾ ⁢ A P C
26 8 25 sylan ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → B ⁢ C P A ‾ = B ‾ ⁢ A P C
27 7 15 26 3eqtr3d ⊢ U ∈ CPreHil OLD ∧ A ∈ X ∧ B ∈ ℂ ∧ C ∈ X → A P B S C = B ‾ ⁢ A P C