Metamath Proof Explorer


Theorem divsfval

Description: Value of the function in qusval . (Contributed by Mario Carneiro, 24-Feb-2015) (Revised by Mario Carneiro, 12-Aug-2015) (Revised by AV, 12-Jul-2024)

Ref Expression
Hypotheses ercpbl.r ⊢ φ → ∼ ˙ Er V
ercpbl.v ⊢ φ → V ∈ W
ercpbl.f ⊢ F = x ∈ V ⟼ x ∼ ˙
Assertion divsfval ⊢ φ → F ⁡ A = A ∼ ˙

Proof

Step Hyp Ref Expression
1 ercpbl.r ⊢ φ → ∼ ˙ Er V
2 ercpbl.v ⊢ φ → V ∈ W
3 ercpbl.f ⊢ F = x ∈ V ⟼ x ∼ ˙
4 1 ecss ⊢ φ → A ∼ ˙ ⊆ V
5 2 4 ssexd ⊢ φ → A ∼ ˙ ∈ V
6 eceq1 ⊢ x = A → x ∼ ˙ = A ∼ ˙
7 6 3 fvmptg ⊢ A ∈ V ∧ A ∼ ˙ ∈ V → F ⁡ A = A ∼ ˙
8 5 7 sylan2 ⊢ A ∈ V ∧ φ → F ⁡ A = A ∼ ˙
9 8 expcom ⊢ φ → A ∈ V → F ⁡ A = A ∼ ˙
10 3 dmeqi ⊢ dom ⁡ F = dom ⁡ x ∈ V ⟼ x ∼ ˙
11 1 ecss ⊢ φ → x ∼ ˙ ⊆ V
12 2 11 ssexd ⊢ φ → x ∼ ˙ ∈ V
13 12 ralrimivw ⊢ φ → ∀ x ∈ V x ∼ ˙ ∈ V
14 dmmptg ⊢ ∀ x ∈ V x ∼ ˙ ∈ V → dom ⁡ x ∈ V ⟼ x ∼ ˙ = V
15 13 14 syl ⊢ φ → dom ⁡ x ∈ V ⟼ x ∼ ˙ = V
16 10 15 eqtrid ⊢ φ → dom ⁡ F = V
17 16 eleq2d ⊢ φ → A ∈ dom ⁡ F ↔ A ∈ V
18 17 notbid ⊢ φ → ¬ A ∈ dom ⁡ F ↔ ¬ A ∈ V
19 ndmfv ⊢ ¬ A ∈ dom ⁡ F → F ⁡ A = ∅
20 18 19 biimtrrdi ⊢ φ → ¬ A ∈ V → F ⁡ A = ∅
21 ecdmn0 ⊢ A ∈ dom ⁡ ∼ ˙ ↔ A ∼ ˙ ≠ ∅
22 erdm ⊢ ∼ ˙ Er V → dom ⁡ ∼ ˙ = V
23 1 22 syl ⊢ φ → dom ⁡ ∼ ˙ = V
24 23 eleq2d ⊢ φ → A ∈ dom ⁡ ∼ ˙ ↔ A ∈ V
25 24 biimpd ⊢ φ → A ∈ dom ⁡ ∼ ˙ → A ∈ V
26 21 25 biimtrrid ⊢ φ → A ∼ ˙ ≠ ∅ → A ∈ V
27 26 necon1bd ⊢ φ → ¬ A ∈ V → A ∼ ˙ = ∅
28 20 27 jcad ⊢ φ → ¬ A ∈ V → F ⁡ A = ∅ ∧ A ∼ ˙ = ∅
29 eqtr3 ⊢ F ⁡ A = ∅ ∧ A ∼ ˙ = ∅ → F ⁡ A = A ∼ ˙
30 28 29 syl6 ⊢ φ → ¬ A ∈ V → F ⁡ A = A ∼ ˙
31 9 30 pm2.61d ⊢ φ → F ⁡ A = A ∼ ˙