Metamath Proof Explorer


Theorem elreal2

Description: Ordered pair membership in the class of complex numbers. (Contributed by Mario Carneiro, 15-Jun-2013) (New usage is discouraged.)

Ref Expression
Assertion elreal2 ⊢ A ∈ ℝ ↔ 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹

Proof

Step Hyp Ref Expression
1 df-r ⊢ ℝ = 𝑹 × 0 𝑹
2 1 eleq2i ⊢ A ∈ ℝ ↔ A ∈ 𝑹 × 0 𝑹
3 xp1st ⊢ A ∈ 𝑹 × 0 𝑹 → 1 st ⁡ A ∈ 𝑹
4 1st2nd2 ⊢ A ∈ 𝑹 × 0 𝑹 → A = 1 st ⁡ A 2 nd ⁡ A
5 xp2nd ⊢ A ∈ 𝑹 × 0 𝑹 → 2 nd ⁡ A ∈ 0 𝑹
6 elsni ⊢ 2 nd ⁡ A ∈ 0 𝑹 → 2 nd ⁡ A = 0 𝑹
7 5 6 syl ⊢ A ∈ 𝑹 × 0 𝑹 → 2 nd ⁡ A = 0 𝑹
8 7 opeq2d ⊢ A ∈ 𝑹 × 0 𝑹 → 1 st ⁡ A 2 nd ⁡ A = 1 st ⁡ A 0 𝑹
9 4 8 eqtrd ⊢ A ∈ 𝑹 × 0 𝑹 → A = 1 st ⁡ A 0 𝑹
10 3 9 jca ⊢ A ∈ 𝑹 × 0 𝑹 → 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹
11 eleq1 ⊢ A = 1 st ⁡ A 0 𝑹 → A ∈ 𝑹 × 0 𝑹 ↔ 1 st ⁡ A 0 𝑹 ∈ 𝑹 × 0 𝑹
12 0r ⊢ 0 𝑹 ∈ 𝑹
13 12 elexi ⊢ 0 𝑹 ∈ V
14 13 snid ⊢ 0 𝑹 ∈ 0 𝑹
15 opelxp ⊢ 1 st ⁡ A 0 𝑹 ∈ 𝑹 × 0 𝑹 ↔ 1 st ⁡ A ∈ 𝑹 ∧ 0 𝑹 ∈ 0 𝑹
16 14 15 mpbiran2 ⊢ 1 st ⁡ A 0 𝑹 ∈ 𝑹 × 0 𝑹 ↔ 1 st ⁡ A ∈ 𝑹
17 11 16 bitrdi ⊢ A = 1 st ⁡ A 0 𝑹 → A ∈ 𝑹 × 0 𝑹 ↔ 1 st ⁡ A ∈ 𝑹
18 17 biimparc ⊢ 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹 → A ∈ 𝑹 × 0 𝑹
19 10 18 impbii ⊢ A ∈ 𝑹 × 0 𝑹 ↔ 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹
20 2 19 bitri ⊢ A ∈ ℝ ↔ 1 st ⁡ A ∈ 𝑹 ∧ A = 1 st ⁡ A 0 𝑹