Metamath Proof Explorer


Theorem gsumprval

Description: Value of the group sum operation over a pair of sequential integers. (Contributed by AV, 14-Dec-2018)

Ref Expression
Hypotheses gsumprval.b ⊢ B = Base G
gsumprval.p ⊢ + ˙ = + G
gsumprval.g ⊢ φ → G ∈ V
gsumprval.m ⊢ φ → M ∈ ℤ
gsumprval.n ⊢ φ → N = M + 1
gsumprval.f ⊢ φ → F : M N ⟶ B
Assertion gsumprval ⊢ φ → ∑ G F = F ⁡ M + ˙ F ⁡ N

Proof

Step Hyp Ref Expression
1 gsumprval.b ⊢ B = Base G
2 gsumprval.p ⊢ + ˙ = + G
3 gsumprval.g ⊢ φ → G ∈ V
4 gsumprval.m ⊢ φ → M ∈ ℤ
5 gsumprval.n ⊢ φ → N = M + 1
6 gsumprval.f ⊢ φ → F : M N ⟶ B
7 uzid ⊢ M ∈ ℤ → M ∈ ℤ ≥ M
8 4 7 syl ⊢ φ → M ∈ ℤ ≥ M
9 peano2uz ⊢ M ∈ ℤ ≥ M → M + 1 ∈ ℤ ≥ M
10 8 9 syl ⊢ φ → M + 1 ∈ ℤ ≥ M
11 fzpr ⊢ M ∈ ℤ → M … M + 1 = M M + 1
12 4 11 syl ⊢ φ → M … M + 1 = M M + 1
13 5 eqcomd ⊢ φ → M + 1 = N
14 13 preq2d ⊢ φ → M M + 1 = M N
15 12 14 eqtrd ⊢ φ → M … M + 1 = M N
16 15 feq2d ⊢ φ → F : M … M + 1 ⟶ B ↔ F : M N ⟶ B
17 6 16 mpbird ⊢ φ → F : M … M + 1 ⟶ B
18 1 2 3 10 17 gsumval2 ⊢ φ → ∑ G F = seq M + ˙ F ⁡ M + 1
19 seqp1 ⊢ M ∈ ℤ ≥ M → seq M + ˙ F ⁡ M + 1 = seq M + ˙ F ⁡ M + ˙ F ⁡ M + 1
20 8 19 syl ⊢ φ → seq M + ˙ F ⁡ M + 1 = seq M + ˙ F ⁡ M + ˙ F ⁡ M + 1
21 seq1 ⊢ M ∈ ℤ → seq M + ˙ F ⁡ M = F ⁡ M
22 4 21 syl ⊢ φ → seq M + ˙ F ⁡ M = F ⁡ M
23 13 fveq2d ⊢ φ → F ⁡ M + 1 = F ⁡ N
24 22 23 oveq12d ⊢ φ → seq M + ˙ F ⁡ M + ˙ F ⁡ M + 1 = F ⁡ M + ˙ F ⁡ N
25 18 20 24 3eqtrd ⊢ φ → ∑ G F = F ⁡ M + ˙ F ⁡ N