Metamath Proof Explorer


Theorem gsumsubg

Description: The group sum in a subgroup is the same as the group sum. (Contributed by Thierry Arnoux, 28-May-2023)

Ref Expression
Hypotheses gsumsubg.1 ⊢ H = G ↾ 𝑠 B
gsumsubg.a ⊢ φ → A ∈ V
gsumsubg.f ⊢ φ → F : A ⟶ B
gsumsubg.b ⊢ φ → B ∈ SubGrp ⁡ G
Assertion gsumsubg ⊢ φ → ∑ G F = ∑ H F

Proof

Step Hyp Ref Expression
1 gsumsubg.1 ⊢ H = G ↾ 𝑠 B
2 gsumsubg.a ⊢ φ → A ∈ V
3 gsumsubg.f ⊢ φ → F : A ⟶ B
4 gsumsubg.b ⊢ φ → B ∈ SubGrp ⁡ G
5 eqid ⊢ Base G = Base G
6 eqid ⊢ + G = + G
7 4 elfvexd ⊢ φ → G ∈ V
8 5 subgss ⊢ B ∈ SubGrp ⁡ G → B ⊆ Base G
9 4 8 syl ⊢ φ → B ⊆ Base G
10 eqid ⊢ 0 G = 0 G
11 10 subg0cl ⊢ B ∈ SubGrp ⁡ G → 0 G ∈ B
12 4 11 syl ⊢ φ → 0 G ∈ B
13 subgrcl ⊢ B ∈ SubGrp ⁡ G → G ∈ Grp
14 4 13 syl ⊢ φ → G ∈ Grp
15 5 6 10 grplid ⊢ G ∈ Grp ∧ x ∈ Base G → 0 G + G x = x
16 5 6 10 grprid ⊢ G ∈ Grp ∧ x ∈ Base G → x + G 0 G = x
17 15 16 jca ⊢ G ∈ Grp ∧ x ∈ Base G → 0 G + G x = x ∧ x + G 0 G = x
18 14 17 sylan ⊢ φ ∧ x ∈ Base G → 0 G + G x = x ∧ x + G 0 G = x
19 5 6 1 7 2 9 3 12 18 gsumress ⊢ φ → ∑ G F = ∑ H F