Metamath Proof Explorer


Theorem gsumxp2

Description: Write a group sum over a cartesian product as a double sum in two ways. This corresponds to the first equation in Lang p. 6. (Contributed by AV, 27-Dec-2023)

Ref Expression
Hypotheses gsumxp2.b ⊢ B = Base G
gsumxp2.z ⊢ 0 ˙ = 0 G
gsumxp2.g ⊢ φ → G ∈ CMnd
gsumxp2.a ⊢ φ → A ∈ V
gsumxp2.r ⊢ φ → C ∈ W
gsumxp2.f ⊢ φ → F : A × C ⟶ B
gsumxp2.w ⊢ φ → finSupp 0 ˙⁡ F
Assertion gsumxp2 ⊢ φ → ∑ G k ∈ C ∑ G j ∈ A j F k = ∑ G j ∈ A ∑ G k ∈ C j F k

Proof

Step Hyp Ref Expression
1 gsumxp2.b ⊢ B = Base G
2 gsumxp2.z ⊢ 0 ˙ = 0 G
3 gsumxp2.g ⊢ φ → G ∈ CMnd
4 gsumxp2.a ⊢ φ → A ∈ V
5 gsumxp2.r ⊢ φ → C ∈ W
6 gsumxp2.f ⊢ φ → F : A × C ⟶ B
7 gsumxp2.w ⊢ φ → finSupp 0 ˙⁡ F
8 6 fovcdmda ⊢ φ ∧ j ∈ A ∧ k ∈ C → j F k ∈ B
9 7 fsuppimpd ⊢ φ → F supp 0 ˙ ∈ Fin
10 simpl ⊢ φ ∧ j ∈ A ∧ k ∈ C → φ
11 opelxpi ⊢ j ∈ A ∧ k ∈ C → j k ∈ A × C
12 11 ad2antlr ⊢ φ ∧ j ∈ A ∧ k ∈ C ∧ ¬ j k ∈ supp 0 ˙⁡ F → j k ∈ A × C
13 simpr ⊢ φ ∧ j ∈ A ∧ k ∈ C ∧ ¬ j k ∈ supp 0 ˙⁡ F → ¬ j k ∈ supp 0 ˙⁡ F
14 12 13 eldifd ⊢ φ ∧ j ∈ A ∧ k ∈ C ∧ ¬ j k ∈ supp 0 ˙⁡ F → j k ∈ A × C ∖ supp 0 ˙⁡ F
15 ssidd ⊢ φ → F supp 0 ˙ ⊆ F supp 0 ˙
16 4 5 xpexd ⊢ φ → A × C ∈ V
17 2 fvexi ⊢ 0 ˙ ∈ V
18 17 a1i ⊢ φ → 0 ˙ ∈ V
19 6 15 16 18 suppssr ⊢ φ ∧ j k ∈ A × C ∖ supp 0 ˙⁡ F → F ⁡ j k = 0 ˙
20 10 14 19 syl2an2r ⊢ φ ∧ j ∈ A ∧ k ∈ C ∧ ¬ j k ∈ supp 0 ˙⁡ F → F ⁡ j k = 0 ˙
21 20 ex ⊢ φ ∧ j ∈ A ∧ k ∈ C → ¬ j k ∈ supp 0 ˙⁡ F → F ⁡ j k = 0 ˙
22 df-br ⊢ j supp 0 ˙⁡ F k ↔ j k ∈ supp 0 ˙⁡ F
23 22 notbii ⊢ ¬ j supp 0 ˙⁡ F k ↔ ¬ j k ∈ supp 0 ˙⁡ F
24 df-ov ⊢ j F k = F ⁡ j k
25 24 eqeq1i ⊢ j F k = 0 ˙ ↔ F ⁡ j k = 0 ˙
26 21 23 25 3imtr4g ⊢ φ ∧ j ∈ A ∧ k ∈ C → ¬ j supp 0 ˙⁡ F k → j F k = 0 ˙
27 26 impr ⊢ φ ∧ j ∈ A ∧ k ∈ C ∧ ¬ j supp 0 ˙⁡ F k → j F k = 0 ˙
28 1 2 3 4 5 8 9 27 gsumcom3 ⊢ φ → ∑ G j ∈ A ∑ G k ∈ C j F k = ∑ G k ∈ C ∑ G j ∈ A j F k
29 28 eqcomd ⊢ φ → ∑ G k ∈ C ∑ G j ∈ A j F k = ∑ G j ∈ A ∑ G k ∈ C j F k