Metamath Proof Explorer


Theorem hdmaprnlem10N

Description: Lemma for hdmaprnN . Show s is in the range of S . (Contributed by NM, 29-May-2015) (New usage is discouraged.)

Ref Expression
Hypotheses hdmaprnlem1.h ⊢ H = LHyp ⁡ K
hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
hdmaprnlem1.v ⊢ V = Base U
hdmaprnlem1.n ⊢ N = LSpan ⁡ U
hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
hdmaprnlem1.l ⊢ L = LSpan ⁡ C
hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
hdmaprnlem1.ve ⊢ φ → v ∈ V
hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
hdmaprnlem1.ue ⊢ φ → u ∈ V
hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
hdmaprnlem1.d ⊢ D = Base C
hdmaprnlem1.q ⊢ Q = 0 C
hdmaprnlem1.o ⊢ 0 ˙ = 0 U
hdmaprnlem1.a ⊢ ✚ ˙ = + C
hdmaprnlem3e.p ⊢ + ˙ = + U
Assertion hdmaprnlem10N ⊢ φ → ∃ t ∈ V S ⁡ t = s

Proof

Step Hyp Ref Expression
1 hdmaprnlem1.h ⊢ H = LHyp ⁡ K
2 hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmaprnlem1.v ⊢ V = Base U
4 hdmaprnlem1.n ⊢ N = LSpan ⁡ U
5 hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
6 hdmaprnlem1.l ⊢ L = LSpan ⁡ C
7 hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
8 hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
9 hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
11 hdmaprnlem1.ve ⊢ φ → v ∈ V
12 hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
13 hdmaprnlem1.ue ⊢ φ → u ∈ V
14 hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
15 hdmaprnlem1.d ⊢ D = Base C
16 hdmaprnlem1.q ⊢ Q = 0 C
17 hdmaprnlem1.o ⊢ 0 ˙ = 0 U
18 hdmaprnlem1.a ⊢ ✚ ˙ = + C
19 hdmaprnlem3e.p ⊢ + ˙ = + U
20 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 hdmaprnlem3eN ⊢ φ → ∃ t ∈ N ⁡ v ∖ 0 ˙ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t
21 9 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → K ∈ HL ∧ W ∈ H
22 10 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → s ∈ D ∖ Q
23 11 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → v ∈ V
24 12 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → M ⁡ N ⁡ v = L ⁡ s
25 13 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → u ∈ V
26 14 adantr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → ¬ u ∈ N ⁡ v
27 simprl ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → t ∈ N ⁡ v ∖ 0 ˙
28 1 2 3 4 5 6 7 8 21 22 23 24 25 26 15 16 17 18 27 hdmaprnlem4tN ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → t ∈ V
29 simprr ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t
30 1 2 3 4 5 6 7 8 21 22 23 24 25 26 15 16 17 18 27 19 29 hdmaprnlem9N ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → s = S ⁡ t
31 30 eqcomd ⊢ φ ∧ t ∈ N ⁡ v ∖ 0 ˙ ∧ L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t → S ⁡ t = s
32 20 28 31 reximssdv ⊢ φ → ∃ t ∈ V S ⁡ t = s