Metamath Proof Explorer


Theorem hdmaprnlem4tN

Description: Lemma for hdmaprnN . TODO: This lemma doesn't quite pay for itself even though used six times. Maybe prove this directly instead. (Contributed by NM, 27-May-2015) (New usage is discouraged.)

Ref Expression
Hypotheses hdmaprnlem1.h ⊢ H = LHyp ⁡ K
hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
hdmaprnlem1.v ⊢ V = Base U
hdmaprnlem1.n ⊢ N = LSpan ⁡ U
hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
hdmaprnlem1.l ⊢ L = LSpan ⁡ C
hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
hdmaprnlem1.ve ⊢ φ → v ∈ V
hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
hdmaprnlem1.ue ⊢ φ → u ∈ V
hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
hdmaprnlem1.d ⊢ D = Base C
hdmaprnlem1.q ⊢ Q = 0 C
hdmaprnlem1.o ⊢ 0 ˙ = 0 U
hdmaprnlem1.a ⊢ ✚ ˙ = + C
hdmaprnlem1.t2 ⊢ φ → t ∈ N ⁡ v ∖ 0 ˙
Assertion hdmaprnlem4tN ⊢ φ → t ∈ V

Proof

Step Hyp Ref Expression
1 hdmaprnlem1.h ⊢ H = LHyp ⁡ K
2 hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmaprnlem1.v ⊢ V = Base U
4 hdmaprnlem1.n ⊢ N = LSpan ⁡ U
5 hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
6 hdmaprnlem1.l ⊢ L = LSpan ⁡ C
7 hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
8 hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
9 hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
11 hdmaprnlem1.ve ⊢ φ → v ∈ V
12 hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
13 hdmaprnlem1.ue ⊢ φ → u ∈ V
14 hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
15 hdmaprnlem1.d ⊢ D = Base C
16 hdmaprnlem1.q ⊢ Q = 0 C
17 hdmaprnlem1.o ⊢ 0 ˙ = 0 U
18 hdmaprnlem1.a ⊢ ✚ ˙ = + C
19 hdmaprnlem1.t2 ⊢ φ → t ∈ N ⁡ v ∖ 0 ˙
20 1 2 9 dvhlmod ⊢ φ → U ∈ LMod
21 11 snssd ⊢ φ → v ⊆ V
22 3 4 lspssv ⊢ U ∈ LMod ∧ v ⊆ V → N ⁡ v ⊆ V
23 20 21 22 syl2anc ⊢ φ → N ⁡ v ⊆ V
24 23 ssdifssd ⊢ φ → N ⁡ v ∖ 0 ˙ ⊆ V
25 24 19 sseldd ⊢ φ → t ∈ V