Metamath Proof Explorer


Theorem hdmaprnlem9N

Description: Part of proof of part 12 in Baer p. 49 line 21, s=S(t). TODO: we seem to be going back and forth with mapd11 and mapdcnv11N . Use better hypotheses and/or theorems? (Contributed by NM, 27-May-2015) (New usage is discouraged.)

Ref Expression
Hypotheses hdmaprnlem1.h ⊢ H = LHyp ⁡ K
hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
hdmaprnlem1.v ⊢ V = Base U
hdmaprnlem1.n ⊢ N = LSpan ⁡ U
hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
hdmaprnlem1.l ⊢ L = LSpan ⁡ C
hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
hdmaprnlem1.ve ⊢ φ → v ∈ V
hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
hdmaprnlem1.ue ⊢ φ → u ∈ V
hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
hdmaprnlem1.d ⊢ D = Base C
hdmaprnlem1.q ⊢ Q = 0 C
hdmaprnlem1.o ⊢ 0 ˙ = 0 U
hdmaprnlem1.a ⊢ ✚ ˙ = + C
hdmaprnlem1.t2 ⊢ φ → t ∈ N ⁡ v ∖ 0 ˙
hdmaprnlem1.p ⊢ + ˙ = + U
hdmaprnlem1.pt ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t
Assertion hdmaprnlem9N ⊢ φ → s = S ⁡ t

Proof

Step Hyp Ref Expression
1 hdmaprnlem1.h ⊢ H = LHyp ⁡ K
2 hdmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmaprnlem1.v ⊢ V = Base U
4 hdmaprnlem1.n ⊢ N = LSpan ⁡ U
5 hdmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
6 hdmaprnlem1.l ⊢ L = LSpan ⁡ C
7 hdmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
8 hdmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
9 hdmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 hdmaprnlem1.se ⊢ φ → s ∈ D ∖ Q
11 hdmaprnlem1.ve ⊢ φ → v ∈ V
12 hdmaprnlem1.e ⊢ φ → M ⁡ N ⁡ v = L ⁡ s
13 hdmaprnlem1.ue ⊢ φ → u ∈ V
14 hdmaprnlem1.un ⊢ φ → ¬ u ∈ N ⁡ v
15 hdmaprnlem1.d ⊢ D = Base C
16 hdmaprnlem1.q ⊢ Q = 0 C
17 hdmaprnlem1.o ⊢ 0 ˙ = 0 U
18 hdmaprnlem1.a ⊢ ✚ ˙ = + C
19 hdmaprnlem1.t2 ⊢ φ → t ∈ N ⁡ v ∖ 0 ˙
20 hdmaprnlem1.p ⊢ + ˙ = + U
21 hdmaprnlem1.pt ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s = M ⁡ N ⁡ u + ˙ t
22 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 hdmaprnlem7N ⊢ φ → s - C S ⁡ t ∈ L ⁡ S ⁡ u ✚ ˙ s
23 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 hdmaprnlem8N ⊢ φ → s - C S ⁡ t ∈ M ⁡ N ⁡ t
24 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 hdmaprnlem4N ⊢ φ → M ⁡ N ⁡ t = L ⁡ s
25 23 24 eleqtrd ⊢ φ → s - C S ⁡ t ∈ L ⁡ s
26 22 25 elind ⊢ φ → s - C S ⁡ t ∈ L ⁡ S ⁡ u ✚ ˙ s ∩ L ⁡ s
27 1 5 9 lcdlvec ⊢ φ → C ∈ LVec
28 1 5 9 lcdlmod ⊢ φ → C ∈ LMod
29 1 2 3 5 15 8 9 13 hdmapcl ⊢ φ → S ⁡ u ∈ D
30 10 eldifad ⊢ φ → s ∈ D
31 15 18 lmodvacl ⊢ C ∈ LMod ∧ S ⁡ u ∈ D ∧ s ∈ D → S ⁡ u ✚ ˙ s ∈ D
32 28 29 30 31 syl3anc ⊢ φ → S ⁡ u ✚ ˙ s ∈ D
33 eqid ⊢ LSubSp ⁡ C = LSubSp ⁡ C
34 15 33 6 lspsncl ⊢ C ∈ LMod ∧ s ∈ D → L ⁡ s ∈ LSubSp ⁡ C
35 28 30 34 syl2anc ⊢ φ → L ⁡ s ∈ LSubSp ⁡ C
36 1 7 5 33 9 mapdrn2 ⊢ φ → ran ⁡ M = LSubSp ⁡ C
37 35 36 eleqtrrd ⊢ φ → L ⁡ s ∈ ran ⁡ M
38 1 7 9 37 mapdcnvid2 ⊢ φ → M ⁡ M -1 ⁡ L ⁡ s = L ⁡ s
39 12 38 eqtr4d ⊢ φ → M ⁡ N ⁡ v = M ⁡ M -1 ⁡ L ⁡ s
40 eqid ⊢ LSubSp ⁡ U = LSubSp ⁡ U
41 1 2 9 dvhlmod ⊢ φ → U ∈ LMod
42 3 40 4 lspsncl ⊢ U ∈ LMod ∧ v ∈ V → N ⁡ v ∈ LSubSp ⁡ U
43 41 11 42 syl2anc ⊢ φ → N ⁡ v ∈ LSubSp ⁡ U
44 1 7 2 40 9 37 mapdcnvcl ⊢ φ → M -1 ⁡ L ⁡ s ∈ LSubSp ⁡ U
45 1 2 40 7 9 43 44 mapd11 ⊢ φ → M ⁡ N ⁡ v = M ⁡ M -1 ⁡ L ⁡ s ↔ N ⁡ v = M -1 ⁡ L ⁡ s
46 39 45 mpbid ⊢ φ → N ⁡ v = M -1 ⁡ L ⁡ s
47 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 hdmaprnlem3N ⊢ φ → N ⁡ v ≠ M -1 ⁡ L ⁡ S ⁡ u ✚ ˙ s
48 46 47 eqnetrrd ⊢ φ → M -1 ⁡ L ⁡ s ≠ M -1 ⁡ L ⁡ S ⁡ u ✚ ˙ s
49 15 33 6 lspsncl ⊢ C ∈ LMod ∧ S ⁡ u ✚ ˙ s ∈ D → L ⁡ S ⁡ u ✚ ˙ s ∈ LSubSp ⁡ C
50 28 32 49 syl2anc ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s ∈ LSubSp ⁡ C
51 50 36 eleqtrrd ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s ∈ ran ⁡ M
52 1 7 9 37 51 mapdcnv11N ⊢ φ → M -1 ⁡ L ⁡ s = M -1 ⁡ L ⁡ S ⁡ u ✚ ˙ s ↔ L ⁡ s = L ⁡ S ⁡ u ✚ ˙ s
53 52 necon3bid ⊢ φ → M -1 ⁡ L ⁡ s ≠ M -1 ⁡ L ⁡ S ⁡ u ✚ ˙ s ↔ L ⁡ s ≠ L ⁡ S ⁡ u ✚ ˙ s
54 48 53 mpbid ⊢ φ → L ⁡ s ≠ L ⁡ S ⁡ u ✚ ˙ s
55 54 necomd ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s ≠ L ⁡ s
56 15 16 6 27 32 30 55 lspdisj2 ⊢ φ → L ⁡ S ⁡ u ✚ ˙ s ∩ L ⁡ s = Q
57 26 56 eleqtrd ⊢ φ → s - C S ⁡ t ∈ Q
58 elsni ⊢ s - C S ⁡ t ∈ Q → s - C S ⁡ t = Q
59 57 58 syl ⊢ φ → s - C S ⁡ t = Q
60 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 hdmaprnlem4tN ⊢ φ → t ∈ V
61 1 2 3 5 15 8 9 60 hdmapcl ⊢ φ → S ⁡ t ∈ D
62 eqid ⊢ - C = - C
63 15 16 62 lmodsubeq0 ⊢ C ∈ LMod ∧ s ∈ D ∧ S ⁡ t ∈ D → s - C S ⁡ t = Q ↔ s = S ⁡ t
64 28 30 61 63 syl3anc ⊢ φ → s - C S ⁡ t = Q ↔ s = S ⁡ t
65 59 64 mpbid ⊢ φ → s = S ⁡ t