Metamath Proof Explorer


Theorem isfieldidl

Description: Determine if a ring is a field based on its ideals. (Contributed by Jeff Madsen, 10-Jun-2010) (Revised by AV, 30-Jun-2026)

Ref Expression
Hypotheses isfieldidl.b B = Base R
isfieldidl.0 0 ˙ = 0 R
isfieldidl.i I = LIdeal R
isfieldidl.1 1 ˙ = 1 R
Assertion isfieldidl R Field R CRing 0 ˙ 1 ˙ I = 0 ˙ B

Proof

Step Hyp Ref Expression
1 isfieldidl.b B = Base R
2 isfieldidl.0 0 ˙ = 0 R
3 isfieldidl.i I = LIdeal R
4 isfieldidl.1 1 ˙ = 1 R
5 isfld R Field R DivRing R CRing
6 1 2 3 drngidl R NzRing R DivRing I = 0 ˙ B
7 6 adantr R NzRing R CRing R DivRing I = 0 ˙ B
8 4 2 nzrnz R NzRing 1 ˙ 0 ˙
9 8 necomd R NzRing 0 ˙ 1 ˙
10 9 a1d R NzRing I = 0 ˙ B 0 ˙ 1 ˙
11 10 adantr R NzRing R CRing I = 0 ˙ B 0 ˙ 1 ˙
12 11 pm4.71rd R NzRing R CRing I = 0 ˙ B 0 ˙ 1 ˙ I = 0 ˙ B
13 7 12 bitrd R NzRing R CRing R DivRing 0 ˙ 1 ˙ I = 0 ˙ B
14 drngnzr R DivRing R NzRing
15 14 con3i ¬ R NzRing ¬ R DivRing
16 15 adantr ¬ R NzRing R CRing ¬ R DivRing
17 ianor ¬ R Ring 1 ˙ 0 ˙ ¬ R Ring ¬ 1 ˙ 0 ˙
18 4 2 isnzr R NzRing R Ring 1 ˙ 0 ˙
19 17 18 xchnxbir ¬ R NzRing ¬ R Ring ¬ 1 ˙ 0 ˙
20 pm2.24 R Ring ¬ R Ring ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
21 crngring R CRing R Ring
22 20 21 syl11 ¬ R Ring R CRing ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
23 id 0 ˙ 1 ˙ 0 ˙ 1 ˙
24 23 necomd 0 ˙ 1 ˙ 1 ˙ 0 ˙
25 24 con3i ¬ 1 ˙ 0 ˙ ¬ 0 ˙ 1 ˙
26 25 orcd ¬ 1 ˙ 0 ˙ ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
27 26 a1d ¬ 1 ˙ 0 ˙ R CRing ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
28 22 27 jaoi ¬ R Ring ¬ 1 ˙ 0 ˙ R CRing ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
29 19 28 sylbi ¬ R NzRing R CRing ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
30 29 imp ¬ R NzRing R CRing ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
31 ianor ¬ 0 ˙ 1 ˙ I = 0 ˙ B ¬ 0 ˙ 1 ˙ ¬ I = 0 ˙ B
32 30 31 sylibr ¬ R NzRing R CRing ¬ 0 ˙ 1 ˙ I = 0 ˙ B
33 16 32 2falsed ¬ R NzRing R CRing R DivRing 0 ˙ 1 ˙ I = 0 ˙ B
34 13 33 pm2.61ian R CRing R DivRing 0 ˙ 1 ˙ I = 0 ˙ B
35 34 pm5.32i R CRing R DivRing R CRing 0 ˙ 1 ˙ I = 0 ˙ B
36 ancom R DivRing R CRing R CRing R DivRing
37 3anass R CRing 0 ˙ 1 ˙ I = 0 ˙ B R CRing 0 ˙ 1 ˙ I = 0 ˙ B
38 35 36 37 3bitr4i R DivRing R CRing R CRing 0 ˙ 1 ˙ I = 0 ˙ B
39 5 38 bitri R Field R CRing 0 ˙ 1 ˙ I = 0 ˙ B