Metamath Proof Explorer


Theorem ishashinf

Description: Any set that is not finite contains subsets of arbitrarily large finite cardinality. Cf. isinf . (Contributed by Thierry Arnoux, 5-Jul-2017)

Ref Expression
Assertion ishashinf ⊢ ¬ A ∈ Fin → ∀ n ∈ ℕ ∃ x ∈ 𝒫 A x = n

Proof

Step Hyp Ref Expression
1 fzfid ⊢ n ∈ ℕ → 1 … n ∈ Fin
2 ficardom ⊢ 1 … n ∈ Fin → card ⁡ 1 … n ∈ ω
3 1 2 syl ⊢ n ∈ ℕ → card ⁡ 1 … n ∈ ω
4 isinf ⊢ ¬ A ∈ Fin → ∀ a ∈ ω ∃ x x ⊆ A ∧ x ≈ a
5 breq2 ⊢ a = card ⁡ 1 … n → x ≈ a ↔ x ≈ card ⁡ 1 … n
6 5 anbi2d ⊢ a = card ⁡ 1 … n → x ⊆ A ∧ x ≈ a ↔ x ⊆ A ∧ x ≈ card ⁡ 1 … n
7 6 exbidv ⊢ a = card ⁡ 1 … n → ∃ x x ⊆ A ∧ x ≈ a ↔ ∃ x x ⊆ A ∧ x ≈ card ⁡ 1 … n
8 7 rspcva ⊢ card ⁡ 1 … n ∈ ω ∧ ∀ a ∈ ω ∃ x x ⊆ A ∧ x ≈ a → ∃ x x ⊆ A ∧ x ≈ card ⁡ 1 … n
9 3 4 8 syl2anr ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → ∃ x x ⊆ A ∧ x ≈ card ⁡ 1 … n
10 velpw ⊢ x ∈ 𝒫 A ↔ x ⊆ A
11 10 biimpri ⊢ x ⊆ A → x ∈ 𝒫 A
12 11 a1i ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → x ⊆ A → x ∈ 𝒫 A
13 hasheni ⊢ x ≈ card ⁡ 1 … n → x = card ⁡ 1 … n
14 13 adantl ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ ∧ x ≈ card ⁡ 1 … n → x = card ⁡ 1 … n
15 hashcard ⊢ 1 … n ∈ Fin → card ⁡ 1 … n = 1 … n
16 1 15 syl ⊢ n ∈ ℕ → card ⁡ 1 … n = 1 … n
17 nnnn0 ⊢ n ∈ ℕ → n ∈ ℕ 0
18 hashfz1 ⊢ n ∈ ℕ 0 → 1 … n = n
19 17 18 syl ⊢ n ∈ ℕ → 1 … n = n
20 16 19 eqtrd ⊢ n ∈ ℕ → card ⁡ 1 … n = n
21 20 ad2antlr ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ ∧ x ≈ card ⁡ 1 … n → card ⁡ 1 … n = n
22 14 21 eqtrd ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ ∧ x ≈ card ⁡ 1 … n → x = n
23 22 ex ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → x ≈ card ⁡ 1 … n → x = n
24 12 23 anim12d ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → x ⊆ A ∧ x ≈ card ⁡ 1 … n → x ∈ 𝒫 A ∧ x = n
25 24 eximdv ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → ∃ x x ⊆ A ∧ x ≈ card ⁡ 1 … n → ∃ x x ∈ 𝒫 A ∧ x = n
26 9 25 mpd ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → ∃ x x ∈ 𝒫 A ∧ x = n
27 df-rex ⊢ ∃ x ∈ 𝒫 A x = n ↔ ∃ x x ∈ 𝒫 A ∧ x = n
28 26 27 sylibr ⊢ ¬ A ∈ Fin ∧ n ∈ ℕ → ∃ x ∈ 𝒫 A x = n
29 28 ralrimiva ⊢ ¬ A ∈ Fin → ∀ n ∈ ℕ ∃ x ∈ 𝒫 A x = n