Metamath Proof Explorer


Theorem ispsubsp

Description: The predicate "is a projective subspace". (Contributed by NM, 2-Oct-2011)

Ref Expression
Hypotheses psubspset.l ⊢ ≤ ˙ = ≤ K
psubspset.j ⊢ ∨ ˙ = join ⁡ K
psubspset.a ⊢ A = Atoms ⁡ K
psubspset.s ⊢ S = PSubSp ⁡ K
Assertion ispsubsp ⊢ K ∈ D → X ∈ S ↔ X ⊆ A ∧ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X

Proof

Step Hyp Ref Expression
1 psubspset.l ⊢ ≤ ˙ = ≤ K
2 psubspset.j ⊢ ∨ ˙ = join ⁡ K
3 psubspset.a ⊢ A = Atoms ⁡ K
4 psubspset.s ⊢ S = PSubSp ⁡ K
5 1 2 3 4 psubspset ⊢ K ∈ D → S = x | x ⊆ A ∧ ∀ p ∈ x ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x
6 5 eleq2d ⊢ K ∈ D → X ∈ S ↔ X ∈ x | x ⊆ A ∧ ∀ p ∈ x ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x
7 3 fvexi ⊢ A ∈ V
8 7 ssex ⊢ X ⊆ A → X ∈ V
9 8 adantr ⊢ X ⊆ A ∧ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X → X ∈ V
10 sseq1 ⊢ x = X → x ⊆ A ↔ X ⊆ A
11 eleq2 ⊢ x = X → r ∈ x ↔ r ∈ X
12 11 imbi2d ⊢ x = X → r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ r ≤ ˙ p ∨ ˙ q → r ∈ X
13 12 ralbidv ⊢ x = X → ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X
14 13 raleqbi1dv ⊢ x = X → ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X
15 14 raleqbi1dv ⊢ x = X → ∀ p ∈ x ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X
16 10 15 anbi12d ⊢ x = X → x ⊆ A ∧ ∀ p ∈ x ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ X ⊆ A ∧ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X
17 9 16 elab3 ⊢ X ∈ x | x ⊆ A ∧ ∀ p ∈ x ∀ q ∈ x ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ x ↔ X ⊆ A ∧ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X
18 6 17 bitrdi ⊢ K ∈ D → X ∈ S ↔ X ⊆ A ∧ ∀ p ∈ X ∀ q ∈ X ∀ r ∈ A r ≤ ˙ p ∨ ˙ q → r ∈ X