Metamath Proof Explorer


Theorem lcdlssvscl

Description: Closure of scalar product in a closed kernel dual vector space. (Contributed by NM, 20-Mar-2015)

Ref Expression
Hypotheses lcdlssvscl.h ⊢ H = LHyp ⁡ K
lcdlssvscl.u ⊢ U = DVecH ⁡ K ⁡ W
lcdlssvscl.f ⊢ F = Scalar ⁡ U
lcdlssvscl.r ⊢ R = Base F
lcdlssvscl.c ⊢ C = LCDual ⁡ K ⁡ W
lcdlssvscl.v ⊢ V = Base C
lcdlssvscl.t ⊢ · ˙ = ⋅ C
lcdlssvscl.s ⊢ S = LSubSp ⁡ C
lcdlssvscl.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcdlssvscl.l ⊢ φ → L ∈ S
lcdlssvscl.x ⊢ φ → X ∈ R
lcdlssvscl.y ⊢ φ → Y ∈ L
Assertion lcdlssvscl ⊢ φ → X · ˙ Y ∈ L

Proof

Step Hyp Ref Expression
1 lcdlssvscl.h ⊢ H = LHyp ⁡ K
2 lcdlssvscl.u ⊢ U = DVecH ⁡ K ⁡ W
3 lcdlssvscl.f ⊢ F = Scalar ⁡ U
4 lcdlssvscl.r ⊢ R = Base F
5 lcdlssvscl.c ⊢ C = LCDual ⁡ K ⁡ W
6 lcdlssvscl.v ⊢ V = Base C
7 lcdlssvscl.t ⊢ · ˙ = ⋅ C
8 lcdlssvscl.s ⊢ S = LSubSp ⁡ C
9 lcdlssvscl.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 lcdlssvscl.l ⊢ φ → L ∈ S
11 lcdlssvscl.x ⊢ φ → X ∈ R
12 lcdlssvscl.y ⊢ φ → Y ∈ L
13 1 5 9 lcdlmod ⊢ φ → C ∈ LMod
14 eqid ⊢ Scalar ⁡ C = Scalar ⁡ C
15 eqid ⊢ Base Scalar ⁡ C = Base Scalar ⁡ C
16 1 2 3 4 5 14 15 9 lcdsbase ⊢ φ → Base Scalar ⁡ C = R
17 11 16 eleqtrrd ⊢ φ → X ∈ Base Scalar ⁡ C
18 14 7 15 8 lssvscl ⊢ C ∈ LMod ∧ L ∈ S ∧ X ∈ Base Scalar ⁡ C ∧ Y ∈ L → X · ˙ Y ∈ L
19 13 10 17 12 18 syl22anc ⊢ φ → X · ˙ Y ∈ L