Metamath Proof Explorer


Theorem ldual0vs

Description: Scalar zero times a functional is the zero functional. (Contributed by NM, 17-Feb-2015)

Ref Expression
Hypotheses ldual0vs.f ⊢ F = LFnl ⁡ W
ldual0vs.r ⊢ R = Scalar ⁡ W
ldual0vs.z ⊢ 0 ˙ = 0 R
ldual0vs.d ⊢ D = LDual ⁡ W
ldual0vs.t ⊢ · ˙ = ⋅ D
ldual0vs.o ⊢ O = 0 D
ldual0vs.w ⊢ φ → W ∈ LMod
ldual0vs.g ⊢ φ → G ∈ F
Assertion ldual0vs ⊢ φ → 0 ˙ · ˙ G = O

Proof

Step Hyp Ref Expression
1 ldual0vs.f ⊢ F = LFnl ⁡ W
2 ldual0vs.r ⊢ R = Scalar ⁡ W
3 ldual0vs.z ⊢ 0 ˙ = 0 R
4 ldual0vs.d ⊢ D = LDual ⁡ W
5 ldual0vs.t ⊢ · ˙ = ⋅ D
6 ldual0vs.o ⊢ O = 0 D
7 ldual0vs.w ⊢ φ → W ∈ LMod
8 ldual0vs.g ⊢ φ → G ∈ F
9 eqid ⊢ Scalar ⁡ D = Scalar ⁡ D
10 eqid ⊢ 0 Scalar ⁡ D = 0 Scalar ⁡ D
11 2 3 4 9 10 7 ldual0 ⊢ φ → 0 Scalar ⁡ D = 0 ˙
12 11 oveq1d ⊢ φ → 0 Scalar ⁡ D · ˙ G = 0 ˙ · ˙ G
13 4 7 lduallmod ⊢ φ → D ∈ LMod
14 eqid ⊢ Base D = Base D
15 1 4 14 7 8 ldualelvbase ⊢ φ → G ∈ Base D
16 14 9 5 10 6 lmod0vs ⊢ D ∈ LMod ∧ G ∈ Base D → 0 Scalar ⁡ D · ˙ G = O
17 13 15 16 syl2anc ⊢ φ → 0 Scalar ⁡ D · ˙ G = O
18 12 17 eqtr3d ⊢ φ → 0 ˙ · ˙ G = O