Metamath Proof Explorer


Theorem lsmidl

Description: The sum of two ideals is an ideal. (Contributed by Thierry Arnoux, 21-Jan-2024)

Ref Expression
Hypotheses lsmidl.1 ⊢ B = Base R
lsmidl.3 ⊢ ⊕ ˙ = LSSum ⁡ R
lsmidl.4 ⊢ K = RSpan ⁡ R
lsmidl.5 ⊢ φ → R ∈ Ring
lsmidl.6 ⊢ φ → I ∈ LIdeal ⁡ R
lsmidl.7 ⊢ φ → J ∈ LIdeal ⁡ R
Assertion lsmidl ⊢ φ → I ⊕ ˙ J ∈ LIdeal ⁡ R

Proof

Step Hyp Ref Expression
1 lsmidl.1 ⊢ B = Base R
2 lsmidl.3 ⊢ ⊕ ˙ = LSSum ⁡ R
3 lsmidl.4 ⊢ K = RSpan ⁡ R
4 lsmidl.5 ⊢ φ → R ∈ Ring
5 lsmidl.6 ⊢ φ → I ∈ LIdeal ⁡ R
6 lsmidl.7 ⊢ φ → J ∈ LIdeal ⁡ R
7 1 2 3 4 5 6 lsmidllsp ⊢ φ → I ⊕ ˙ J = K ⁡ I ∪ J
8 rlmlmod ⊢ R ∈ Ring → ringLMod ⁡ R ∈ LMod
9 4 8 syl ⊢ φ → ringLMod ⁡ R ∈ LMod
10 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
11 1 10 lidlss ⊢ I ∈ LIdeal ⁡ R → I ⊆ B
12 5 11 syl ⊢ φ → I ⊆ B
13 1 10 lidlss ⊢ J ∈ LIdeal ⁡ R → J ⊆ B
14 6 13 syl ⊢ φ → J ⊆ B
15 12 14 unssd ⊢ φ → I ∪ J ⊆ B
16 rlmbas ⊢ Base R = Base ringLMod ⁡ R
17 1 16 eqtri ⊢ B = Base ringLMod ⁡ R
18 lidlval ⊢ LIdeal ⁡ R = LSubSp ⁡ ringLMod ⁡ R
19 rspval ⊢ RSpan ⁡ R = LSpan ⁡ ringLMod ⁡ R
20 3 19 eqtri ⊢ K = LSpan ⁡ ringLMod ⁡ R
21 17 18 20 lspcl ⊢ ringLMod ⁡ R ∈ LMod ∧ I ∪ J ⊆ B → K ⁡ I ∪ J ∈ LIdeal ⁡ R
22 9 15 21 syl2anc ⊢ φ → K ⁡ I ∪ J ∈ LIdeal ⁡ R
23 7 22 eqeltrd ⊢ φ → I ⊕ ˙ J ∈ LIdeal ⁡ R