Metamath Proof Explorer


Theorem ltexp2a

Description: Exponent ordering relationship for exponentiation of a fixed real base greater than 1 to integer exponents. (Contributed by NM, 2-Aug-2006) (Revised by Mario Carneiro, 4-Jun-2014)

Ref Expression
Assertion ltexp2a ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A M < A N

Proof

Step Hyp Ref Expression
1 simpl1 ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A ∈ ℝ
2 0red ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 0 ∈ ℝ
3 1red ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 ∈ ℝ
4 0lt1 ⊢ 0 < 1
5 4 a1i ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 0 < 1
6 simprl ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 < A
7 2 3 1 5 6 lttrd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 0 < A
8 1 7 elrpd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A ∈ ℝ +
9 simpl2 ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → M ∈ ℤ
10 rpexpcl ⊢ A ∈ ℝ + ∧ M ∈ ℤ → A M ∈ ℝ +
11 8 9 10 syl2anc ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A M ∈ ℝ +
12 11 rpred ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A M ∈ ℝ
13 12 recnd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A M ∈ ℂ
14 13 mullidd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 ⁢ A M = A M
15 simprr ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → M < N
16 simpl3 ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → N ∈ ℤ
17 znnsub ⊢ M ∈ ℤ ∧ N ∈ ℤ → M < N ↔ N − M ∈ ℕ
18 9 16 17 syl2anc ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → M < N ↔ N − M ∈ ℕ
19 15 18 mpbid ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → N − M ∈ ℕ
20 expgt1 ⊢ A ∈ ℝ ∧ N − M ∈ ℕ ∧ 1 < A → 1 < A N − M
21 1 19 6 20 syl3anc ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 < A N − M
22 1 recnd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A ∈ ℂ
23 7 gt0ne0d ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A ≠ 0
24 expsub ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ N ∈ ℤ ∧ M ∈ ℤ → A N − M = A N A M
25 22 23 16 9 24 syl22anc ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A N − M = A N A M
26 21 25 breqtrd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 < A N A M
27 rpexpcl ⊢ A ∈ ℝ + ∧ N ∈ ℤ → A N ∈ ℝ +
28 8 16 27 syl2anc ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A N ∈ ℝ +
29 28 rpred ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A N ∈ ℝ
30 3 29 11 ltmuldivd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 ⁢ A M < A N ↔ 1 < A N A M
31 26 30 mpbird ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → 1 ⁢ A M < A N
32 14 31 eqbrtrrd ⊢ A ∈ ℝ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ 1 < A ∧ M < N → A M < A N