Metamath Proof Explorer


Theorem mulsubaddmulsub

Description: A special difference of a product with a product of a sum and a difference. (Contributed by AV, 5-Mar-2023)

Ref Expression
Assertion mulsubaddmulsub ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C − A + B ⁢ C − D = A ⁢ D + B ⁢ D - A ⁢ C

Proof

Step Hyp Ref Expression
1 simplr ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ∈ ℂ
2 simprl ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → C ∈ ℂ
3 1 2 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C ∈ ℂ
4 subaddmulsub ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ ∧ B ⁢ C ∈ ℂ → B ⁢ C − A + B ⁢ C − D = B ⁢ C - A ⁢ C - B ⁢ C + A ⁢ D + B ⁢ D
5 3 4 mpd3an3 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C − A + B ⁢ C − D = B ⁢ C - A ⁢ C - B ⁢ C + A ⁢ D + B ⁢ D
6 simpll ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → A ∈ ℂ
7 6 2 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → A ⁢ C ∈ ℂ
8 3 7 3 sub32d ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - A ⁢ C - B ⁢ C = B ⁢ C - B ⁢ C - A ⁢ C
9 3 subidd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C − B ⁢ C = 0
10 9 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - B ⁢ C - A ⁢ C = 0 − A ⁢ C
11 8 10 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - A ⁢ C - B ⁢ C = 0 − A ⁢ C
12 df-neg ⊢ − A ⁢ C = 0 − A ⁢ C
13 11 12 eqtr4di ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - A ⁢ C - B ⁢ C = − A ⁢ C
14 13 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - A ⁢ C - B ⁢ C + A ⁢ D + B ⁢ D = − A ⁢ C + A ⁢ D + B ⁢ D
15 7 negcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → − A ⁢ C ∈ ℂ
16 simprr ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → D ∈ ℂ
17 6 16 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → A ⁢ D ∈ ℂ
18 1 16 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ D ∈ ℂ
19 17 18 addcld ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → A ⁢ D + B ⁢ D ∈ ℂ
20 15 19 addcomd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → − A ⁢ C + A ⁢ D + B ⁢ D = A ⁢ D + B ⁢ D + − A ⁢ C
21 19 7 negsubd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → A ⁢ D + B ⁢ D + − A ⁢ C = A ⁢ D + B ⁢ D - A ⁢ C
22 20 21 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → − A ⁢ C + A ⁢ D + B ⁢ D = A ⁢ D + B ⁢ D - A ⁢ C
23 14 22 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C - A ⁢ C - B ⁢ C + A ⁢ D + B ⁢ D = A ⁢ D + B ⁢ D - A ⁢ C
24 5 23 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℂ → B ⁢ C − A + B ⁢ C − D = A ⁢ D + B ⁢ D - A ⁢ C