Metamath Proof Explorer


Theorem n0nsn2el

Description: If a class with one element is not a singleton, there is at least another element in this class. (Contributed by AV, 6-Mar-2025)

Ref Expression
Assertion n0nsn2el ⊢ A ∈ B ∧ B ≠ A → ∃ x ∈ B x ≠ A

Proof

Step Hyp Ref Expression
1 ne0i ⊢ A ∈ B → B ≠ ∅
2 eqsn ⊢ B ≠ ∅ → B = A ↔ ∀ x ∈ B x = A
3 1 2 syl ⊢ A ∈ B → B = A ↔ ∀ x ∈ B x = A
4 3 biimprd ⊢ A ∈ B → ∀ x ∈ B x = A → B = A
5 4 con3d ⊢ A ∈ B → ¬ B = A → ¬ ∀ x ∈ B x = A
6 df-ne ⊢ B ≠ A ↔ ¬ B = A
7 nne ⊢ ¬ x ≠ A ↔ x = A
8 7 bicomi ⊢ x = A ↔ ¬ x ≠ A
9 8 ralbii ⊢ ∀ x ∈ B x = A ↔ ∀ x ∈ B ¬ x ≠ A
10 ralnex ⊢ ∀ x ∈ B ¬ x ≠ A ↔ ¬ ∃ x ∈ B x ≠ A
11 9 10 bitri ⊢ ∀ x ∈ B x = A ↔ ¬ ∃ x ∈ B x ≠ A
12 11 con2bii ⊢ ∃ x ∈ B x ≠ A ↔ ¬ ∀ x ∈ B x = A
13 5 6 12 3imtr4g ⊢ A ∈ B → B ≠ A → ∃ x ∈ B x ≠ A
14 13 imp ⊢ A ∈ B ∧ B ≠ A → ∃ x ∈ B x ≠ A