Metamath Proof Explorer


Theorem odid

Description: Any element to the power of its order is the identity. (Contributed by Mario Carneiro, 14-Jan-2015) (Revised by Stefan O'Rear, 5-Sep-2015)

Ref Expression
Hypotheses odcl.1 ⊢ X = Base G
odcl.2 ⊢ O = od ⁡ G
odid.3 ⊢ · ˙ = ⋅ G
odid.4 ⊢ 0 ˙ = 0 G
Assertion odid ⊢ A ∈ X → O ⁡ A · ˙ A = 0 ˙

Proof

Step Hyp Ref Expression
1 odcl.1 ⊢ X = Base G
2 odcl.2 ⊢ O = od ⁡ G
3 odid.3 ⊢ · ˙ = ⋅ G
4 odid.4 ⊢ 0 ˙ = 0 G
5 oveq1 ⊢ O ⁡ A = 0 → O ⁡ A · ˙ A = 0 · ˙ A
6 1 4 3 mulg0 ⊢ A ∈ X → 0 · ˙ A = 0 ˙
7 5 6 sylan9eqr ⊢ A ∈ X ∧ O ⁡ A = 0 → O ⁡ A · ˙ A = 0 ˙
8 7 adantrr ⊢ A ∈ X ∧ O ⁡ A = 0 ∧ y ∈ ℕ | y · ˙ A = 0 ˙ = ∅ → O ⁡ A · ˙ A = 0 ˙
9 oveq1 ⊢ y = O ⁡ A → y · ˙ A = O ⁡ A · ˙ A
10 9 eqeq1d ⊢ y = O ⁡ A → y · ˙ A = 0 ˙ ↔ O ⁡ A · ˙ A = 0 ˙
11 10 elrab ⊢ O ⁡ A ∈ y ∈ ℕ | y · ˙ A = 0 ˙ ↔ O ⁡ A ∈ ℕ ∧ O ⁡ A · ˙ A = 0 ˙
12 11 simprbi ⊢ O ⁡ A ∈ y ∈ ℕ | y · ˙ A = 0 ˙ → O ⁡ A · ˙ A = 0 ˙
13 12 adantl ⊢ A ∈ X ∧ O ⁡ A ∈ y ∈ ℕ | y · ˙ A = 0 ˙ → O ⁡ A · ˙ A = 0 ˙
14 eqid ⊢ y ∈ ℕ | y · ˙ A = 0 ˙ = y ∈ ℕ | y · ˙ A = 0 ˙
15 1 3 4 2 14 odlem1 ⊢ A ∈ X → O ⁡ A = 0 ∧ y ∈ ℕ | y · ˙ A = 0 ˙ = ∅ ∨ O ⁡ A ∈ y ∈ ℕ | y · ˙ A = 0 ˙
16 8 13 15 mpjaodan ⊢ A ∈ X → O ⁡ A · ˙ A = 0 ˙