Metamath Proof Explorer


Theorem omess0

Description: If the outer measure of a set is 0 , then the outer measure of its subsets is 0 . (Contributed by Glauco Siliprandi, 24-Dec-2020)

Ref Expression
Hypotheses omess0.o ⊢ φ → O ∈ OutMeas
omess0.x ⊢ X = ⋃ dom ⁡ O
omess0.a ⊢ φ → A ⊆ X
omess0.z ⊢ φ → O ⁡ A = 0
omess0.s ⊢ φ → B ⊆ A
Assertion omess0 ⊢ φ → O ⁡ B = 0

Proof

Step Hyp Ref Expression
1 omess0.o ⊢ φ → O ∈ OutMeas
2 omess0.x ⊢ X = ⋃ dom ⁡ O
3 omess0.a ⊢ φ → A ⊆ X
4 omess0.z ⊢ φ → O ⁡ A = 0
5 omess0.s ⊢ φ → B ⊆ A
6 5 3 sstrd ⊢ φ → B ⊆ X
7 1 2 6 omexrcl ⊢ φ → O ⁡ B ∈ ℝ *
8 0xr ⊢ 0 ∈ ℝ *
9 8 a1i ⊢ φ → 0 ∈ ℝ *
10 1 2 3 5 omessle ⊢ φ → O ⁡ B ≤ O ⁡ A
11 10 4 breqtrd ⊢ φ → O ⁡ B ≤ 0
12 1 2 6 omege0 ⊢ φ → 0 ≤ O ⁡ B
13 7 9 11 12 xrletrid ⊢ φ → O ⁡ B = 0