Metamath Proof Explorer


Theorem ordelinel

Description: The intersection of two ordinal classes is an element of a third if and only if either one of them is. (Contributed by David Moews, 1-May-2017) (Proof shortened by JJ, 24-Sep-2021)

Ref Expression
Assertion ordelinel ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ C → A ∩ B ∈ C ↔ A ∈ C ∨ B ∈ C

Proof

Step Hyp Ref Expression
1 ordtri2or3 ⊢ Ord ⁡ A ∧ Ord ⁡ B → A = A ∩ B ∨ B = A ∩ B
2 1 3adant3 ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ C → A = A ∩ B ∨ B = A ∩ B
3 eleq1a ⊢ A ∩ B ∈ C → A = A ∩ B → A ∈ C
4 eleq1a ⊢ A ∩ B ∈ C → B = A ∩ B → B ∈ C
5 3 4 orim12d ⊢ A ∩ B ∈ C → A = A ∩ B ∨ B = A ∩ B → A ∈ C ∨ B ∈ C
6 2 5 syl5com ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ C → A ∩ B ∈ C → A ∈ C ∨ B ∈ C
7 ordin ⊢ Ord ⁡ A ∧ Ord ⁡ B → Ord ⁡ A ∩ B
8 inss1 ⊢ A ∩ B ⊆ A
9 ordtr2 ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ C → A ∩ B ⊆ A ∧ A ∈ C → A ∩ B ∈ C
10 8 9 mpani ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ C → A ∈ C → A ∩ B ∈ C
11 inss2 ⊢ A ∩ B ⊆ B
12 ordtr2 ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ C → A ∩ B ⊆ B ∧ B ∈ C → A ∩ B ∈ C
13 11 12 mpani ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ C → B ∈ C → A ∩ B ∈ C
14 10 13 jaod ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ C → A ∈ C ∨ B ∈ C → A ∩ B ∈ C
15 7 14 stoic3 ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ C → A ∈ C ∨ B ∈ C → A ∩ B ∈ C
16 6 15 impbid ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ C → A ∩ B ∈ C ↔ A ∈ C ∨ B ∈ C