Metamath Proof Explorer


Theorem ovn0

Description: For any finite dimension, the Lebesgue outer measure of the empty set is zero. This is step (ii) of the proof of Proposition 115D (a) of Fremlin1 p. 30. (Contributed by Glauco Siliprandi, 11-Oct-2020)

Ref Expression
Hypothesis ovn0.1 ⊢ φ → X ∈ Fin
Assertion ovn0 ⊢ φ → voln* ⁡ X ⁡ ∅ = 0

Proof

Step Hyp Ref Expression
1 ovn0.1 ⊢ φ → X ∈ Fin
2 0ss ⊢ ∅ ⊆ ℝ X
3 2 a1i ⊢ φ → ∅ ⊆ ℝ X
4 0ss ⊢ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k
5 4 a1i ⊢ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k → ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k
6 id ⊢ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k → z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
7 5 6 jca ⊢ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k → ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
8 simpr ⊢ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k → z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
9 7 8 impbii ⊢ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ↔ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
10 9 rexbii ⊢ ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ↔ ∃ i ∈ ℝ 2 X ℕ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
11 10 rgenw ⊢ ∀ z ∈ ℝ * ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ↔ ∃ i ∈ ℝ 2 X ℕ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
12 rabbi ⊢ ∀ z ∈ ℝ * ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ↔ ∃ i ∈ ℝ 2 X ℕ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ↔ z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k = z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
13 11 12 mpbi ⊢ z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k = z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ ∅ ⊆ ⋃ j ∈ ℕ ⨉ k ∈ X . ∘ i ⁡ j ⁡ k ∧ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
14 1 3 13 ovnval2 ⊢ φ → voln* ⁡ X ⁡ ∅ = if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * <
15 simpr ⊢ φ ∧ X = ∅ → X = ∅
16 15 iftrued ⊢ φ ∧ X = ∅ → if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = 0
17 iffalse ⊢ ¬ X = ∅ → if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * <
18 17 adantl ⊢ φ ∧ ¬ X = ∅ → if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * <
19 1 adantr ⊢ φ ∧ ¬ X = ∅ → X ∈ Fin
20 neqne ⊢ ¬ X = ∅ → X ≠ ∅
21 20 adantl ⊢ φ ∧ ¬ X = ∅ → X ≠ ∅
22 eqid ⊢ z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k = z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k
23 14 17 sylan9eq ⊢ φ ∧ ¬ X = ∅ → voln* ⁡ X ⁡ ∅ = inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * <
24 23 eqcomd ⊢ φ ∧ ¬ X = ∅ → inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = voln* ⁡ X ⁡ ∅
25 1 ovnf ⊢ φ → voln* ⁡ X : 𝒫 ℝ X ⟶ 0 +∞
26 0elpw ⊢ ∅ ∈ 𝒫 ℝ X
27 26 a1i ⊢ φ → ∅ ∈ 𝒫 ℝ X
28 25 27 ffvelcdmd ⊢ φ → voln* ⁡ X ⁡ ∅ ∈ 0 +∞
29 28 adantr ⊢ φ ∧ ¬ X = ∅ → voln* ⁡ X ⁡ ∅ ∈ 0 +∞
30 24 29 eqeltrd ⊢ φ ∧ ¬ X = ∅ → inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < ∈ 0 +∞
31 eqidd ⊢ m = l → 1 0 = 1 0
32 31 cbvmptv ⊢ m ∈ X ⟼ 1 0 = l ∈ X ⟼ 1 0
33 32 a1i ⊢ h = j → m ∈ X ⟼ 1 0 = l ∈ X ⟼ 1 0
34 33 cbvmptv ⊢ h ∈ ℕ ⟼ m ∈ X ⟼ 1 0 = j ∈ ℕ ⟼ l ∈ X ⟼ 1 0
35 19 21 22 30 34 ovn0lem ⊢ φ ∧ ¬ X = ∅ → inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = 0
36 18 35 eqtrd ⊢ φ ∧ ¬ X = ∅ → if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = 0
37 16 36 pm2.61dan ⊢ φ → if X = ∅ 0 inf z ∈ ℝ * | ∃ i ∈ ℝ 2 X ℕ z = sum^ ⁡ j ∈ ℕ ⟼ ∏ k ∈ X vol ⁡ . ∘ i ⁡ j ⁡ k ℝ * < = 0
38 14 37 eqtrd ⊢ φ → voln* ⁡ X ⁡ ∅ = 0