Metamath Proof Explorer


Theorem ply1vr1smo

Description: The variable in a polynomial expressed as scaled monomial. (Contributed by AV, 12-Aug-2019)

Ref Expression
Hypotheses ply1vr1smo.p ⊢ P = Poly 1 ⁡ R
ply1vr1smo.i ⊢ 1 ˙ = 1 R
ply1vr1smo.t ⊢ · ˙ = ⋅ P
ply1vr1smo.m ⊢ G = mulGrp P
ply1vr1smo.e ⊢ × ˙ = ⋅ G
ply1vr1smo.x ⊢ X = var 1 ⁡ R
Assertion ply1vr1smo ⊢ R ∈ Ring → 1 ˙ · ˙ 1 × ˙ X = X

Proof

Step Hyp Ref Expression
1 ply1vr1smo.p ⊢ P = Poly 1 ⁡ R
2 ply1vr1smo.i ⊢ 1 ˙ = 1 R
3 ply1vr1smo.t ⊢ · ˙ = ⋅ P
4 ply1vr1smo.m ⊢ G = mulGrp P
5 ply1vr1smo.e ⊢ × ˙ = ⋅ G
6 ply1vr1smo.x ⊢ X = var 1 ⁡ R
7 1 ply1sca ⊢ R ∈ Ring → R = Scalar ⁡ P
8 7 fveq2d ⊢ R ∈ Ring → 1 R = 1 Scalar ⁡ P
9 2 8 eqtrid ⊢ R ∈ Ring → 1 ˙ = 1 Scalar ⁡ P
10 9 oveq1d ⊢ R ∈ Ring → 1 ˙ · ˙ 1 × ˙ X = 1 Scalar ⁡ P · ˙ 1 × ˙ X
11 1 ply1lmod ⊢ R ∈ Ring → P ∈ LMod
12 eqid ⊢ Base P = Base P
13 6 1 12 vr1cl ⊢ R ∈ Ring → X ∈ Base P
14 4 12 mgpbas ⊢ Base P = Base G
15 14 5 mulg1 ⊢ X ∈ Base P → 1 × ˙ X = X
16 13 15 syl ⊢ R ∈ Ring → 1 × ˙ X = X
17 16 13 eqeltrd ⊢ R ∈ Ring → 1 × ˙ X ∈ Base P
18 eqid ⊢ Scalar ⁡ P = Scalar ⁡ P
19 eqid ⊢ 1 Scalar ⁡ P = 1 Scalar ⁡ P
20 12 18 3 19 lmodvs1 ⊢ P ∈ LMod ∧ 1 × ˙ X ∈ Base P → 1 Scalar ⁡ P · ˙ 1 × ˙ X = 1 × ˙ X
21 11 17 20 syl2anc ⊢ R ∈ Ring → 1 Scalar ⁡ P · ˙ 1 × ˙ X = 1 × ˙ X
22 10 21 16 3eqtrd ⊢ R ∈ Ring → 1 ˙ · ˙ 1 × ˙ X = X