Metamath Proof Explorer


Theorem psrnzr

Description: The ring of power series over a nonzero ring form a nonzero ring. (Contributed by Thierry Arnoux, 4-May-2026)

Ref Expression
Hypotheses psrnzr.s S = I mPwSer R
psrnzr.i φ I V
psrnzr.r φ R NzRing
Assertion psrnzr φ S NzRing

Proof

Step Hyp Ref Expression
1 psrnzr.s S = I mPwSer R
2 psrnzr.i φ I V
3 psrnzr.r φ R NzRing
4 nzrring R NzRing R Ring
5 3 4 syl φ R Ring
6 1 2 5 psrring φ S Ring
7 eqid 1 R = 1 R
8 eqid 0 R = 0 R
9 7 8 nzrnz R NzRing 1 R 0 R
10 3 9 syl φ 1 R 0 R
11 eqid h 0 I | h -1 Fin = h 0 I | h -1 Fin
12 eqid 1 S = 1 S
13 1 2 5 11 8 7 12 psr1 φ 1 S = x h 0 I | h -1 Fin if x = I × 0 1 R 0 R
14 simpr φ x = I × 0 x = I × 0
15 14 iftrued φ x = I × 0 if x = I × 0 1 R 0 R = 1 R
16 11 psrbag0 I V I × 0 h 0 I | h -1 Fin
17 2 16 syl φ I × 0 h 0 I | h -1 Fin
18 fvexd φ 1 R V
19 13 15 17 18 fvmptd φ 1 S I × 0 = 1 R
20 5 ringgrpd φ R Grp
21 eqid 0 S = 0 S
22 1 2 20 11 8 21 psr0 φ 0 S = h 0 I | h -1 Fin × 0 R
23 22 fveq1d φ 0 S I × 0 = h 0 I | h -1 Fin × 0 R I × 0
24 fvex 0 R V
25 24 fvconst2 I × 0 h 0 I | h -1 Fin h 0 I | h -1 Fin × 0 R I × 0 = 0 R
26 17 25 syl φ h 0 I | h -1 Fin × 0 R I × 0 = 0 R
27 23 26 eqtrd φ 0 S I × 0 = 0 R
28 10 19 27 3netr4d φ 1 S I × 0 0 S I × 0
29 fveq1 1 S = 0 S 1 S I × 0 = 0 S I × 0
30 29 necon3i 1 S I × 0 0 S I × 0 1 S 0 S
31 28 30 syl φ 1 S 0 S
32 12 21 isnzr S NzRing S Ring 1 S 0 S
33 6 31 32 sylanbrc φ S NzRing