Metamath Proof Explorer


Theorem reprfi2

Description: Corollary of reprinfz1 . (Contributed by Thierry Arnoux, 15-Dec-2021)

Ref Expression
Hypotheses reprinfz1.n ⊢ φ → N ∈ ℕ 0
reprinfz1.s ⊢ φ → S ∈ ℕ 0
reprinfz1.a ⊢ φ → A ⊆ ℕ
Assertion reprfi2 ⊢ φ → A repr ⁡ S N ∈ Fin

Proof

Step Hyp Ref Expression
1 reprinfz1.n ⊢ φ → N ∈ ℕ 0
2 reprinfz1.s ⊢ φ → S ∈ ℕ 0
3 reprinfz1.a ⊢ φ → A ⊆ ℕ
4 1 2 3 reprinfz1 ⊢ φ → A repr ⁡ S N = A ∩ 1 … N repr ⁡ S N
5 inss2 ⊢ A ∩ 1 … N ⊆ 1 … N
6 fz1ssnn ⊢ 1 … N ⊆ ℕ
7 5 6 sstri ⊢ A ∩ 1 … N ⊆ ℕ
8 7 a1i ⊢ φ → A ∩ 1 … N ⊆ ℕ
9 1 nn0zd ⊢ φ → N ∈ ℤ
10 fzfi ⊢ 1 … N ∈ Fin
11 10 a1i ⊢ φ → 1 … N ∈ Fin
12 5 a1i ⊢ φ → A ∩ 1 … N ⊆ 1 … N
13 11 12 ssfid ⊢ φ → A ∩ 1 … N ∈ Fin
14 8 9 2 13 reprfi ⊢ φ → A ∩ 1 … N repr ⁡ S N ∈ Fin
15 4 14 eqeltrd ⊢ φ → A repr ⁡ S N ∈ Fin