Metamath Proof Explorer


Theorem rngqiprngim

Description: F is an isomorphism of non-unital rings. (Contributed by AV, 21-Feb-2025)

Ref Expression
Hypotheses rng2idlring.r ⊢ φ → R ∈ Rng
rng2idlring.i ⊢ φ → I ∈ 2Ideal ⁡ R
rng2idlring.j ⊢ J = R ↾ 𝑠 I
rng2idlring.u ⊢ φ → J ∈ Ring
rng2idlring.b ⊢ B = Base R
rng2idlring.t ⊢ · ˙ = ⋅ R
rng2idlring.1 ⊢ 1 ˙ = 1 J
rngqiprngim.g ⊢ ∼ ˙ = R ~ QG I
rngqiprngim.q ⊢ Q = R / 𝑠 ∼ ˙
rngqiprngim.c ⊢ C = Base Q
rngqiprngim.p ⊢ P = Q × 𝑠 J
rngqiprngim.f ⊢ F = x ∈ B ⟼ x ∼ ˙ 1 ˙ · ˙ x
Assertion rngqiprngim ⊢ φ → F ∈ R RngIso P

Proof

Step Hyp Ref Expression
1 rng2idlring.r ⊢ φ → R ∈ Rng
2 rng2idlring.i ⊢ φ → I ∈ 2Ideal ⁡ R
3 rng2idlring.j ⊢ J = R ↾ 𝑠 I
4 rng2idlring.u ⊢ φ → J ∈ Ring
5 rng2idlring.b ⊢ B = Base R
6 rng2idlring.t ⊢ · ˙ = ⋅ R
7 rng2idlring.1 ⊢ 1 ˙ = 1 J
8 rngqiprngim.g ⊢ ∼ ˙ = R ~ QG I
9 rngqiprngim.q ⊢ Q = R / 𝑠 ∼ ˙
10 rngqiprngim.c ⊢ C = Base Q
11 rngqiprngim.p ⊢ P = Q × 𝑠 J
12 rngqiprngim.f ⊢ F = x ∈ B ⟼ x ∼ ˙ 1 ˙ · ˙ x
13 1 2 3 4 5 6 7 8 9 10 11 12 rngqiprngho ⊢ φ → F ∈ R RngHom P
14 1 2 3 4 5 6 7 8 9 10 11 12 rngqiprngimf1 ⊢ φ → F : B ⟶ 1-1 C × I
15 1 2 3 4 5 6 7 8 9 10 11 12 rngqiprngimfo ⊢ φ → F : B ⟶ onto C × I
16 df-f1o ⊢ F : B ⟶ 1-1 onto C × I ↔ F : B ⟶ 1-1 C × I ∧ F : B ⟶ onto C × I
17 14 15 16 sylanbrc ⊢ φ → F : B ⟶ 1-1 onto C × I
18 1 2 3 4 5 6 7 8 9 10 11 rngqipbas ⊢ φ → Base P = C × I
19 18 f1oeq3d ⊢ φ → F : B ⟶ 1-1 onto Base P ↔ F : B ⟶ 1-1 onto C × I
20 17 19 mpbird ⊢ φ → F : B ⟶ 1-1 onto Base P
21 11 ovexi ⊢ P ∈ V
22 eqid ⊢ Base P = Base P
23 5 22 isrngim2 ⊢ R ∈ Rng ∧ P ∈ V → F ∈ R RngIso P ↔ F ∈ R RngHom P ∧ F : B ⟶ 1-1 onto Base P
24 1 21 23 sylancl ⊢ φ → F ∈ R RngIso P ↔ F ∈ R RngHom P ∧ F : B ⟶ 1-1 onto Base P
25 13 20 24 mpbir2and ⊢ φ → F ∈ R RngIso P